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nataly862011 [7]
3 years ago
13

What is the x- coordinate of the solution to the system of equations? 0.1x+0.5y=0.6 0.4x-1.2y=-5.6

Mathematics
1 answer:
Fiesta28 [93]3 years ago
4 0
We have that

<span>0.1x+0.5y=0.6
0.4x-1.2y=-5.6

using  a graph tool
see the attached figure

the solution is the point (-6.5,2.5)

the answer is
the coordinate x of the solution is x=-6.5

</span>

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A square scarf has a side length of 3/4 yard on each side what is the area of the scarf??
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Answer:

3 unit

Step-by-step explanation:

3/4 x 4 = 12/4 = 3

6 0
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What is the answer to this problem<br> -69=7v-6
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A projectile is fired with muzzle speed 220 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe
Allushta [10]

Answer:

  • 4968.6 m from where it was fired
  • 221.33 m/s

Step-by-step explanation:

For the purpose of this problem, we assume ballistic motion over a stationary flat Earth under the influence of gravity, with no air resistance.

We can divide the motion into two components, one vertical and one horizontal. For muzzle speed s and launch angle θ, the horizontal speed is presumed constant at s·cos(θ). The initial vertical speed is then s·sin(θ) and the (x, y) coordinates as a function of time are ...

  (x, y) = (s·cos(θ)·t, -4.9t² +s·sin(θ)·t + h₀) . . . . . where h₀ is the initial height

To find the range, we can solve the equation y=0 for t, and use this value of t to find x.

Using the quadratic formula, we find t at the time of landing to be ...

  t = (-s·sin(θ) - √((s·sin(θ))²-4(-4.9)(h₀)))/(2(-4.9))

  t = (s/9.8)(sin(θ) +√(sin(θ)² +19.6h₀/s²))

For s = 220, θ = 45°, and h₀ = 30, the time of flight is ...

  t ≈ 31.939 seconds

Then the horizontal travel is

  x = 220·cos(45°)·31.939 ≈ 4968.6 . . . . meters

__

As it happens, the value under the radical in the above expression for time, when multiplied by s, is the vertical speed at landing. The horizontal speed remains s·cos(θ), so the resultant speed is the Pythagorean sum of these:

  landing speed = s·√(cos(θ)² +sin(θ)² +19.6h₀/s²) ≈ s√(1 +0.012149)

  ≈ 221.33 m/s

_____

Note that the landing speed represents the speed the projectile has as a consequence of the potential energy of its initial height being converted to kinetic energy that adds to the kinetic energy due to its initial muzzle velocity.

6 0
2 years ago
Suppose 86% of 50 people at a law firm like their job. How many people like their job.
solniwko [45]
To find 86% of 50, you do 50*.86 (because .86 is the decimal form of the percentage 86%)

50*.86=43 people

Hope this helps
8 0
3 years ago
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A 20-foot ladder is leaning against a tree. The bottom of the ladder is 12 feet away from the bottom of the tree. Approximately
jarptica [38.1K]

Using the Pythagorean Theorem we can solve.


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3 years ago
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