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3 years ago

The hypotenuse of a 45-45-90 triangle measures 4 cm. What Is the length of one leg of the triangle

Mathematics

2 answers:

Allisa [31]3 years ago

7 0

Answer:

2.83 cm.

Step-by-step explanation:

We have been given that the hypotenuse of a 45-45-90 triangle measures 4 cm. We are asked to find the length of one leg of triangle.

We know that hypotenuse of 45-45-90 triangle is $x\sqrt{2}$ and each leg is x units.

We are told that hypotenuse of triangle is 4 cm, so we can set an equation as:

$x\sqrt{2}=4$

$\frac{x\sqrt{2}}{\sqrt{2}}=\frac{4}{\sqrt{2}}$

$x=2.82842712474$

$x\approx 2.83$

Therefore, the length of each leg of triangle is approximately 2.83 cm.

murzikaleks [220]3 years ago

4 0

Check the picture below.

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Give the answer of this question by using prime factorization in exponential form 486×768

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3 years ago

The 12th term of the arithmetic sequence is 10.5. The 18th term of this sequence is 13.5. Find the common difference and the fir

xxMikexx [17]

Answer:

common difference is 0.5

first term is 5

Step-by-step explanation:

use the formula for the nth term of an ap Tn=a+(n-1)d

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therefore come up with two equations

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3 years ago

Solve the equation. \dfrac32 + b = \dfrac74 2 3 +b= 4 7 start fraction, 3, divided by, 2, end fraction, plus, b, equals, sta

Xelga [282]

Given:

The equation is

$\dfrac{3}{2}+b=\dfrac{7}{4}$

To find:

The value of b.

Solution:

We have,

$\dfrac{3}{2}+b=\dfrac{7}{4}$

Subtracting both sides by $\dfrac{3}{2}$ , we get

$b=\dfrac{7}{4}-\dfrac{3}{2}$

$b=\dfrac{7-2(3)}{4}$

$b=\dfrac{7-6}{4}$

$b=\dfrac{1}{4}$

Therefore, the value of b is $\dfrac{1}{4}$ .

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3 years ago

Read 2 more answers

Solve the inequality 4t^2 ≤ 9t-2 please show steps and interval notation. thank you!

Misha Larkins [42]

Answer:

[0.25, 2]

Step-by-step explanation:

We have

4t² ≤ 9t-2

subtract 9t-2 from both sides to make this a quadratic

4t²-9t+2 ≤ 0

To solve this, we can solve for 4t²-9t+2=0 and do some guess and check to find which values result in the function being less than 0.

4t²-9t+2=0

We can see that -8 and -1 add up to -9, the coefficient of t, and 4 (the coefficient of t²) and 2 multiply to 8, which is also equal to -8 * -1. Therefore, we can write this as

4t²-8t-t+2=0

4t(t-2)-1(t-2)=0

(4t-1)(t-2)=0

Our zeros are thus t=2 and t = 1/4. Using these zeros, we can set up three zones: t < 1/4, 1/4<t<2, and t>2. We can take one random value from each of these zones and see if it fits the criteria of

4t²-9t+2 ≤ 0

For t<1/4, we can plug in 0. 4(0)²-9(0) + 2 = 2 >0 , so this is not correct

For 1/4<t<2, we can plug 1 in. 4(1)²-9(1) +2 = -3 <0, so this is correct

For t > 2, we can plug 5 in. 4(5)²-9(5) + 2 = 57 > 0, so this is not correct.

Therefore, for 4t^2 ≤ 9t-2 , which can also be written as 4t²-9t+2 ≤ 0, when t is between 1/4 and 2, the inequality is correct. Furthermore, as the sides are equal when t= 1/4 and t=2, this can be written as [0.25, 2]

8 0

3 years ago