Answer: the length of the field is 70 yards. The width of the field is 35 yards
Step-by-step explanation:
Let L represent the length of the rectangular athletic field.
Let W represent the width of the rectangular athletic field.
A rectangular athletic field is twice as long as it is wide. This means that
L = 2W
The formula for determining the perimeter of a rectangle is expressed as
Perimeter = 2(L + W)
If the perimeter of the athletic field is 210 yards, it means that
210 = 2(L + W)
L + W = 210/2 = 105
Substituting L = 2W into L + W = 105, it becomes
2W + W = 105
3W = 105
W = 105/3 = 35
L = 2W = 2 × 35
L = 70
3x +6 = x^2-2x
x^2-5x-6 =0 , which is quardic equation..
solving , we will get, x = 6 or x= -1
hope it helped
1. 12a+6=12a+6
2. 12a+6=12a+2
3. 12a+6=4a+6
4. 12a+6=7a+5
Answer:
True
Step-by-step explanation:
False
True
False
True
True