This would be easiest to do by completing the square.
x^2+10x-2=0
x^2+10x=2
x^2+10x+25=27
(x+5)^2=27
x+5=±√27
x=-5±√27
(x+5+√27)(x+5-√27)
hii!
n(n-4) = 60
n^2 - 4n - 60 = 0
( n - 10 )(n + 6 ) = 0
n-10 = 0 ---> n = 10 ---> 10*(10-4) = 10*6 = 60
n+6 = 0 --> n = -6 ---> -6 * (-6-4) = -6 * -10 = 60
Answer:
Should be 5 1/2 if thats on there
Step-by-step explanation:
u take 11/2 and take out the 1 u get 10/2 so u cut 10 in half get 5 then add the one and make it 5 1/2
Answer:
Step-by-step explanation:
Comment
If two secants intersect outside a circle (as these two do) then the angle at which they meet is 1/2 the difference between the intersected arcs. Put much simpler <DCF = 1/2 (arc EG - arc DF)
Givens
Arc EG = 127
Arc DF = 49
Solution
<DCF = 1/2(127 - 49)
<DCF = 1/2(78)
<DCF = 39
Answer:
Step-by-step explanation:
your welcome
