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sergij07 [2.7K]
2 years ago
15

In this unit, you’re working with a variety of methods for solving quadratic equations. Which method do you prefer over the othe

rs? Describe the method in your own words, and give an example of a quadratic equation that could be solved with this method. Show and explain the steps for solving the equation.
Mathematics
1 answer:
saveliy_v [14]2 years ago
3 0

Answer:

I believe using the formula is the best method.

Step-by-step explanation:

If I am able to remember the formula this becomes the easiest method in my opinion. It is very simple and anyone can do it if the know basic algebrA.

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What is the slope of the equation 3x - 4y = 32?<br> -3/4<br> -8<br> 3/4<br> 8
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Answer:

y=34x−8

Step-by-step explanation:

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Find all solutions to the equation. cos^2x + 2 cos x + 1 = 0
Black_prince [1.1K]

Answer:

x = pi, 3pi, 5pi  etc

x = -pi, -3pi, -5pi etc

Step-by-step explanation:

cos^2 x + 2 cos x + 1 = 0

replace cos x with m

m^2 + 2m +1 = 0

solve by factoring  (this is a^2 +2ab+b^2 = (a+b)^2  where a =m and b=1)

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3 0
3 years ago
$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e
ch4aika [34]

Answer:

The Amount invested at 7% interest is $12,855

The Amount invested at 6% interest = $1,102  

Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = p_1  = $A

And The money invested at 6% = p_2 = $13957 - $A

Let The interest earn at 7% = I_1

And The interest earn at 6% = I_2

I_1 -  I_2 = $833.73

Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or,  I_1 = \dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}

Or,  I_1 = \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}

And

I_2 = \dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}

Or,  I_2 = \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}

∵  I_1 -  I_2 = $833.73

So, \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100} -  \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100} = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = \dfrac{167115}{13}

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102   . Answer

8 0
3 years ago
Plz help ASAP!!!!!!!!!<br><br> thanks
iogann1982 [59]

Answer:

D (Last one)

Step-by-step explanation:

Reflections and rotations dont change the side lengths or angles of a shape, dilations do.

7 0
3 years ago
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