That's a <em>rhombus</em>. If it has one interior right angle, then
it's a special case of rhombus known as a "square".
Answer:
Step-by-step explanation:
<u>Explanation</u><u>:</u>
On taking LHS
Cos[(3π/2)+θ]Cos(2π+θ)[Cot{(3π/2)-θ}+Cot(2π+θ)]
We know that
π = 180°
2π = 2×180° = 360°
3π/2 = (3×180°)/2 = 540°/2 = 270°
Now
LHS becomes
Cos(270°+θ)Cos(360°+θ)[Cot(270°-θ)+Cot(360°+θ)]
We know that
Cos (270°+θ) = Sin θ
Cos (360°+θ) = Cos θ
Cot (270°-θ) = Tan θ
Cot (360°+θ) = Cot θ
→ Sin θ Cos θ [Tan θ + Cot θ]
→ Sinθ Cosθ[(Sinθ/Cosθ)+(Cosθ/Sinθ)]
→ Sinθ Cosθ[(Sin²θ+Cos²θ)/(SinθCosθ)]
→ Sin θ Cos θ [1/(Sin θ Cos θ)]
Since Sin²θ+Cos²θ = 1
→ (Sin θ Cos θ)/(Sin θ Cos θ)
→ 1
→ RHS
→ LHS = RHS
<u>Hence, Proved.</u>
Here are the formulae that I have used:
→ π = 180°
→ Cos (270°+θ) = Sin θ
→ Cos (360°+θ) = Cos θ
→ Cot (270°-θ) = Tan θ
→ Cot (360°+θ) = Cot θ
Here are the Trigonometric Identities that I have used:
→ Sin²θ+Cos²θ = 1
Answer: The conclusion is valid
Step-by-step explanation:
Number of students surveyed = 50
Number of students who visited a science museum = 20
Number of students who haven't visited a science museum = 30
Percentage of student that have visited a Science museum:
= 20/50 × 100
= 40%
The conclusion is valid based on the calculation.
Write the given equation as
x = (1/2)y² or as y = √(2x)
Graph the given curve within the region (0,0) and (2,2) as shown in the figure below.
When the curve is rotated about the x-axis, an element of surface area is
dA = 2πy dx
The surface area of the resulting solid is
If the right end is considered, the extra area is π*(2²) = 4π
Answer:
The surface area of the rotated solid is (16π)/3.
If the right end is considered, it is an extra area of 4π.