I'll walk you through the first one, and then you should be able to do the rest.
The first step is to right out your numbers from least to greatest
Problem #1: 2,4,5,6,8,10,13,17,19,20
To find the MEDIAN, you're simply crossing out a number from each end until you meet in the middle. In this case, you have an even number of data, which means once you get to the middle, you're have to find the average.
In this problem, your two middle numbers are 8 & 10. Since only one number can be the median, you add them together, and divide by 2:
8+10=18 18/2=9 < this is your middle, or MEDIAN
Next, your first and third quartiles-- they're the median of the lower half and data, and upper half.
For the lower quartile, find the mean of 2,4,5,6, and 8. again, cross out one from each side until you get to the middle. FIRST QUARTILE = 5
Do the same process for the upper half of data (10,13,17,19 & 20).
THIRD QUARTILE = 17
The MIN is the lowest number of data = 2
The MAX is the highest number of data = 20
Best of luck!
The answer to the question is X=1/3
Answer:
b/c+30
Step-by-step explanation:
Answer:- B , C and F are the right options.
Explanation:-
1. HA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.
2. HL can be a reason to show given triangles are congruent as the triangles are right triangle with equal legs and hypotenuse.
3. SAS can be a reason to show given triangles are congruent as there are two congruent sides in both triangles and included angles ∠A=∠D=90° [right angle].
4. LA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.
5. AAS cannot be a reason to show given triangles are congruent as it is not given that they have two angles common in both the triangles.
6.SSS can be a reason to show given triangles are congruent as it is shown that all the sides of one triangle is congruent to the other.
