Answer:
gbtgbrthrefhrthtgrfdhtygfghtygfdghetygfvcdheyrgvfh56trgfh56jytgfvbg546trgfvcyh5tgfffdgnhefsdhyedfhgfeg
Step-by-step explanation:
Answer:
Option A.
Step-by-step explanation:
The given question is incomplete. Here is the complete question.
P(n) models the price (in dollars) of a pack of n bulbs at a certain store.
When does the price of a pack increase faster ?
n 4 10 12
P(n) 12 25 28
When does the price of a pack increase faster ?
A. Between 4 and 10 bulbs
B. Between 10 and 12 bulbs
C. The price increases at the same rat over both the intervals.
To solve this question we will find the rate of increase in the prices per pack in the given intervals.
From n = 4 to n = 10
Rate of increase in price = 
= 
= 2.166 ≈ $2.17 per pack
From n = 10 to n = 12
Rate of increase in price = 
=
= $1.5 per pack
Therefore, price per pack increases faster between n = 4 and n = 10 as compared to n = 10 to n = 12.
Option A is the answer.
Answer:

Step-by-step explanation:
To use the least number of terms, simplify the expression. To simplify, distribute into the parenthesis and combine like terms.

Answer:
Right now I'm wondering what kind of class you are taking to get such a weird graph, but I graphed it for you on the screenie.
Step-by-step explanation:
You should though recheck your question for exponents, as 9x2 could be interpreted differently.
Since exponents to not transition well here, I can assume that it was a 9x^2, so please add an exponent symbol ^ between the variables and exponents next time.
3(2a+1)=-5(a+6)
First expand the brackets.
6a+3=-5a-30
Now add 5a to both sides.
11a+3=-30
Then subtract 3 from both sides.
11a=-33
Finally divide both sides by 11.
a=- 33/11
=-3