3 years ago

List three ways to express 3^5 as a product of powers

1 answer:

6 0

1) 3^2 × 3^3 = (3×3)×(3×3×3) = 9×27 = 243

2) 3^1 × (3^4) = 3×(3×3×3×3) = 3×81 = 243

3) 3^0 × (3^5) = 1×(3×3×3×3×3) = 243

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(5+2g)exp5 for g=-2<br> help pls

Sidana [21]

The value of the expression when g = -2 is -1

<h3>How to simplify the expression</h3>

Given the expression;

(5+2g)exp5

(5+2g)^5

For g = -2

Let's substitute the value of g in the expression

= ( 5 + 2 ( -2) ) ^5

Expand the bracket

= ( 5 - 4) ^ 5

Find the difference

= (-1) ^5

= -1

Thus, the value of the expression when g = -2 is -1

Learn more about algebraic expressions here:

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1 year ago

What is 0.11 as a fraction in simplest form

bazaltina [42]

11 hundredths , or 11/100

3 0

3 years ago

Determine if the equation 4x^2 - 6y^2 = 144 represents an ellipse or a hyperbola, then determine if the ellipse or hyperbola is

PilotLPTM [1.2K]

It represents a horizontal hyperbole

8 0

3 years ago

Question : WHICH OF THE LINES IS PARALLEL ? HOW DO YOU KNOW ?

aleksandr82 [10.1K]

Answer:

B and R

I think that is the name of the lines. If not the the first two lines!!!!

8 0

2 years ago

n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,

Nitella [24]

Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

$A = Pe^{rt}$

Where,

P = initial population,

r = growth rate per period,

t = number of periods,

Given,

The population in 2000, P = 2,400,

Growth rate per year = 1.68% = 0.0168,

Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

$A=2400 e^{0.0168\times 20}$

$=2400 e^{0.336}$

$= 3358.4136$

$\approx 3358$

6 0

3 years ago