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Scilla [17]
2 years ago
15

How to i put

alt="y^{2} +20x+8y+156=0" align="absmiddle" class="latex-formula"> into standard form
Mathematics
1 answer:
Svetllana [295]2 years ago
4 0

Answer:

y=−4+2√5(−x−7)

y=−4−2√5(−x−7)

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Determine whether the statement is true or false, and explain why.
Zielflug [23.3K]

Answer:

False

Step-by-step explanation:

In this case, i woudnt reccomend to use integration by parts, becuase you are not simplifying the expression by doing an integration and a derivation. It is not easy to integrate 1/x³+1, and if you derivate it, then a natural logarithm would appear, and the integral wont be easier after this parts step.

It is a better idea to use integration by substitution. Note that if you replace x³+1 by a variable y, we have that dy = 3x² dx. We can easily make a 3xdx appear in the integral by multiplying and dividing by 3, solving the integral easily:

\int\limits_0^1 x^2/x^3+1 \, dx = 1/3 * \int\limits_1^2 du/u = (ln(2) - ln(1) )/3

(Note that, if x ranges from 0 to 1, then u = x³+1 ranges from 0³+1 = 1 to 1³+1 = 2)

4 0
3 years ago
How can an expression written in either radical form or rational exponent form be rewritten to fit the other form?
adell [148]
When dealing with radicals and exponents, one must realize that fractional exponents deals directly with radicals. In that sense, sqrt(x) = x^1/2
Now, how to go about doing this: 

In a fractional exponent, the numerator represents the actual exponent of the number. So, for x^2/3, the x is being squared. 

For the denominator, that deals with the radical. The index, to be exact. The index describes what KIND of radical (or root) is being taken: square, cube, fourth, fifth, and so on. So, for our example x^2/3, x is squared, and that quantity is under a cube root (or a radical with a 3). Here are some more examples to help you understand a bit more:
x^6/5 = Fifth root of x^6
x^3/1 = x^3
^^^Exponential fractions still follow the same rules of simplifying, so...
x^2/4 = x^1/2 = sqrt(x)

Hope this helps!
8 0
3 years ago
Help me please im dumb​
baherus [9]

You're not dumb! Don't say that :)

Answer: A. Yes

B. 1 feet by 11 feet

Step-by-step explanation: Area = length x width

8 0
3 years ago
Someone help me please
o-na [289]

Answer:

A

Step-by-step explanation:

3 0
2 years ago
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