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Scilla [17]
1 year ago
15

How to i put

alt="y^{2} +20x+8y+156=0" align="absmiddle" class="latex-formula"> into standard form
Mathematics
1 answer:
Svetllana [295]1 year ago
4 0

Answer:

y=−4+2√5(−x−7)

y=−4−2√5(−x−7)

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The answer for this question
Ivanshal [37]
I'm pretty sure it would be 4 5/6 - 3 2/3 = 1 1/6.
3 0
3 years ago
Find the value of x (3/5)^x(5/3)^2x=125/27​
lesya692 [45]

Given:

The equation is

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

To find:

The value of x.

Solution:

We have,

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

\left(\dfrac{5}{3}\right)^{-x}\left(\dfrac{5}{3}\right)^{2x}=\dfrac{5\times 5\times 5}{3\times 3\times 3}      [\because \left(\dfrac{a}{b}\right)^{-m}=\left(\dfrac{b}{a}\right)^{m}]

\left(\dfrac{5}{3}\right)^{-x+2x}=\dfrac{5^3}{3^3}          [\because a^ma^n=a^{m+n}]

\left(\dfrac{5}{3}\right)^{x}=\left(\dfrac{5}{3}\right)^{3}

On comparing the exponents, we get

x=3

Therefore, the value of x is 3.

8 0
2 years ago
Evaluate the expression: 2x + 5 for x = 3
lubasha [3.4K]

Substitute the value of the variable into the equation and simplify.
11
11
5 0
2 years ago
Protozoa are single-celled organisms. Paramecium aurelia is one type of protozoan. The number of paramecium aurelia doubles ever
Sphinxa [80]

Answer:

16 days

Step-by-step explanation:

Given that:

Number of paramecium Aurelia doubles every 1.25days

5 days ago ; number of paramecium Aurelia = 1

How many are there now?

Using the relation :

Multiplier^(total number of days / time it takes to multiply)

Multiplier = doubles = 2

Total number rof days =. 5

Time it takes to. Multiply = 1.25

The formula becomes :

Number(n) of ptotozoan in 5days is given by 2^(5/1.25)

n = 2^(5/1.25)

n = 2^4

n = 2 * 2 * 2 * 2 =. 16

5 0
2 years ago
Please help with this math question!
alisha [4.7K]

Use\ a^\frac{n}{m}=\sqrt[m]{a^n}.\\\\4^\frac{3}{5}=\boxed{\sqrt[5]{4^3}}=\boxed{\sqrt[5]{64}}

5 0
2 years ago
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