15.12m2 just finished the test
This system has one solution y=8x+9, y=x^2+4x+13. What is the y coordinate
y=8x+9<= y=8x+9 <== 8x+9: m=8
y=x^2+4x+13<= y <==x^2+4x+13: minimum (-2,9)
y=8x+9 and y.No solution
Answer:
26.3
It’s really simple actually
Answer:
x=2
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
2x−1−1=x−3−(−5+x)
2x−1−1=x−3+−1(−5+x)(Distribute the Negative Sign)
2x−1−1=x+−3+(−1)(−5)+−1x
2x−1−1=x+−3+5+−x
2x+−1+−1=x+−3+5+−x
(2x)+(−1+−1)=(x+−x)+(−3+5)(Combine Like Terms)
2x+−2=2
2x−2=2
Step 2: Add 2 to both sides.
2x−2+2=2+2
2x=4
Step 3: Divide both sides by 2.
2x
2
=
4
2
x=2
Answer:
Step-by-step explanation:
the function -16t^2 + 64t + 192 give the height S, in ft, of a model water rocket launched with a velocity of 64 ft/second from a hill that is 192 ft high. a) determine how long it will take the rocket to reach the ground, b) find the interval on which the height of the rocket is greater than 240 ft.
