2 years ago

Hello I need a little here with this

Mathematics

1 answer:

Tomtit [17]2 years ago

5 0

I may be wrong but I believe that <1=<2

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(x-3y+ 3z=-4 2x+3y-z =15 (4x-3y- z=19 - What is the solution to the system?

lesya [120]

Answer:

x=5,y=1 and z=-2

Step-by-step explanation:

We are given that system of equation

$x-3y+3z=-4$ (I equation)

$2x+3y-z=15$ (II equation )

$4x-3y-z=19$ (III equation )

Equation II multiply by 3 then add with equation I

Then, we get

$7x+6y=41$ ....(Equation IV)

Subtract equation II from equation III then we get

$2x-6y=4$ (equation V)

Adding equation IV and equation V then, we get

$9x=45$

$x=5$

Substitute x=5 in equation V then, we get

$2(5)-6y=4$

$10-6y=4$

$6y=10-4=6$

$y=1$

Substitute x=5 and y=1 in equation then, we get

$5-3(1)+3z=-4$

$2+3z=-4$

$3z=-4-2=-6$

$z=\frac{-6}{3}=-2$

Hence, the solution for the given system of equation is given by

x=5,y=1 and z=-2

7 0

3 years ago

For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d =

enyata [817]

Given that For a certain model of car the distance $d$ required to stop the vehicle if it is traveling at $v$ mi/h is given by the formula $d=v+\frac{v^2}{20}, where [tex]d$ is measured in feet.

If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

$v+ \frac{v^2}{20} \leq75 \\ \\ 20v+v^2\leq1,500 \\ \\ v^2+20v+100\leq1,500+100 \\ \\ (v+10)^2\leq1,600 \\ \\ |v+10|\leq\sqrt{1,600} \\ \\ -40\leq v+10\leq40 \\ \\ -40-10\leqv\leq v\leq40-10 \\ \\ -50\leq v\leq30$

Therefore, the range of speed she can travel is $v\leq30\ mi/hr$

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B0.81%7D" id="TexFormula1" title="\sqrt{0.81}" alt="\sqrt{0.81}" align="absmiddle" cl

Mandarinka [93]

Answer: .9

Step-by-step explanation:

3 0

3 years ago

You spend $40 on a meal including tax and want to leave a tip that is 20% of the $40. What is the total cost, with the tip?

fenix001 [56]

Your total would be $48.00

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