Answer:
m∠1= 80
m∠2= 100
m∠3= 80
Step-by-step explanation:
Given: m∠1= 2x +40
m∠2= 2y +40
m∠3= x +2y
m∠1 +m∠2= 180 (adj. ∠s on a str. line)
2x +40 +2y +40= 180
2x +2y+ 80= 180
2x +2y= 180 -80
2x +2y= 100
2(x +y)= 100
x +y= 100 ÷2
x +y= 50 -----(1)
m∠1= m∠3 (vert. opp. ∠s)
2x +40= x +2y
2x -x +40= 2y
x= 2y -40 -----(2)
Substitute equation (2) into (1):
2y -40 +y= 50
3y= 50 +40
3y= 90
y= 90 ÷3
y= 30
Substitute y= 30 into equation (2):
x= 2(30) -40
x= 60 -40
x= 20
m∠1
= 2x +40
= 2(20) +40
= 40 +40
= 80
m∠2
= 2y +40
= 2(30) +40
= 60 +40
= 100
m∠3
= x +2y
= 20 +2(30)
= 20 +60
= 80
Alternatively, since m∠1= m∠3,
m∠3
= m∠1 (vert. opp. ∠s)
= 80
Answer:
the answer for this one is A
Step-by-step explanation:
mostly because for this you're only looking for H and not the rest of them so if you reflect is itll be in the same spot just on the opposite side
Answer:
(a) (x+1)(x-1)
(b)(3x+1)(3x-1)
(c) (x+3)(x+5)
(d)(2x+5)(2x+3)
(e)(x+y)(x-y)
(f) 
Step-by-step explanation:
We have to factorize the following expressions:
(a) x²-1 =(x+1)(x-1) (Answer) {Since we know the formula (a²-b²) =(a+b)(a-b)}
(b) 9x²-1 =(3x+1)(3x-1) (Answer) {Since we know the formula (a²-b²) =(a+b)(a-b)}
(c) x²+8x+15 = x² +3x+5x+15 =(x+3)(x+5) (Answer)
(d) 4x²+16x+15 =4x²+10x+6x+15 = 2x(2x+5) +3(2x+5) =(2x+5)(2x+3) (Answer)
(e) x²-y² =(x+y)(x-y) (Answer)
(f) 
(Answer) {Since we know the formula (a²-b²) =(a+b)(a-b)}
Answer:
A ≈ 530 cm²
Step-by-step explanation:
The swept area equals the total area covered by the blade minus the unswept area.
The area of a sector with radius r and angle θ is:
A = (θ / 360) πr²
So the swept area is:
A = (θ / 360) πR² − (θ / 360) πr²
A = (θ / 360) π (R² − r²)
A = (150 / 360) π (21² − 6²)
A ≈ 530 cm²
