PLEASE HELP ITS A TIMED TEST! Jerry has 2 1/2 pounds of peanuts to share equally. He plans to share the peanuts among 5 people.
2 answers:
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Answer:
The sample size necessary is of 168.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Z-table as such z has a p-value of .
That is z with a pvalue of , so Z = 1.96.
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
Based on a previous study, arrival delay times have a standard deviation of 39.6 minutes.
This means that
Find the sample size necessary to estimate the mean arrival delay time for all American Airlines flights from Dallas to Sacramento to within 6 minutes with 95% confidence.
This is n for which M = 6. So
Rounding up:
The sample size necessary is of 168.