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3 years ago

5

PLEASE HELP ITS A TIMED TEST! Jerry has 2 1/2 pounds of peanuts to share equally. He plans to share the peanuts among 5 people.

How many pounds of peanuts will each person get? Express your answer in simplest form.

2 answers:

Anuta_ua [19.1K]3 years ago

7 0

2 1/2 divided by 5=.5 everyone gets 1/2 of a pound. Good luck :)

makkiz [27]3 years ago

3 0

4.2 i think it is btw pm me

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B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =

jolli1 [7]

I suppose you mean

$g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)$

Differentiate one term at a time.

Rewrite the first term as

$\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}$

Then the product rule says

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'$

Then with the power and chain rules,

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}$

Simplify this a bit by factoring out $\frac12 (36-x^2)^{-3/2}$ :

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}$

For the second term, recall that

$\left(\sin^{-1}(x)\right)' = \dfrac1{\sqrt{1-x^2}}$

Then by the chain rule,

$\left(18\sin^{-1}\left(\dfrac x6\right)\right)' = 18 \left(\sin^{-1}\left(\dfrac x6\right)\right)' \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac x6\right)'}{\sqrt{1 - \left(\frac x6\right)^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac16\right)}{\sqrt{1 - \frac{x^2}{36}}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{3}{\frac16\sqrt{36 - x^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18}{\sqrt{36 - x^2}} = 18 (36-x^2)^{-1/2}$

So we have

$g'(x) = 18 (36-x^2)^{-3/2} + 18 (36-x^2)^{-1/2}$

and we can simplify this by factoring out $18(36-x^2)^{-3/2}$ to end up with

$g'(x) = 18(36-x^2)^{-3/2} \left(1 + (36-x^2)\right) = \boxed{18 (36 - x^2)^{-3/2} (37-x^2)}$

5 0

3 years ago

OlgaM077 [116]

Answer: D

Step-by-step explanation:

g(x)=f(x-2)=8(x-2)+1=8x-16+1=8x-15

5 0

2 years ago

Read 2 more answers

Pls help asap!!!!!!!!!!!!!!

fomenos

A c’(-8,1), d’ (-6,5), e’ (-2,4)

6 0

3 years ago

A rental car agency charges $210.00 per week plus 0.25 per mile to rent a car. How many miles can you travel in one week for $34

Greeley [361]

Answer:

548 miles

Step-by-step explanation:

O.25m + 210 = 347

0.25m = 347 - 210

0.25m = 137

m = 137/0.25

m = 548

4 0

3 years ago

PLEASE SOLVE, ITS REALLY EASY, AND IM ON A TIMER..... EEEEEEE

mart [117]

Answer:

What are the choices? How are we supposed to solve it? Seriously man

Step-by-step explanation:

7 0

4 years ago