Answer:
The largest possible volume of the box is 2000000 cubic meters.
Step-by-step explanation:
The volume (
), in cubic centimeters, and surface area (
), in square centimeters, of the box with a square base are described below:
(1)
(2)
Where:
- Side length of the base, in centimeters.
- Height of the box, in centimeters.
By (2), we clear
within the formula:
![h = \frac{V}{l^{2}}](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7BV%7D%7Bl%5E%7B2%7D%7D)
And we apply in (1) and simplify the resulting expression:
![A_{s} = l^{2}+ \frac{V}{l}](https://tex.z-dn.net/?f=A_%7Bs%7D%20%3D%20l%5E%7B2%7D%2B%20%5Cfrac%7BV%7D%7Bl%7D)
![A_{s}\cdot l = l^{3}+V](https://tex.z-dn.net/?f=A_%7Bs%7D%5Ccdot%20l%20%3D%20l%5E%7B3%7D%2BV)
(3)
Then, we find the first and second derivatives of this expression:
(4)
(5)
If
and
, then we find the critical value of the side length of the base is:
![30000-3\cdot l^{2} = 0](https://tex.z-dn.net/?f=30000-3%5Ccdot%20l%5E%7B2%7D%20%3D%200)
![3\cdot l^{2} = 30000](https://tex.z-dn.net/?f=3%5Ccdot%20l%5E%7B2%7D%20%3D%2030000)
![l = 100\,cm](https://tex.z-dn.net/?f=l%20%3D%20100%5C%2Ccm)
Then, we evaluate this result in the expression of the second derivative:
![V'' = -600](https://tex.z-dn.net/?f=V%27%27%20%3D%20-600)
By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:
![V = 30000\cdot l - l^{3}](https://tex.z-dn.net/?f=V%20%3D%2030000%5Ccdot%20l%20-%20l%5E%7B3%7D)
![V = 2000000\,cm^{3}](https://tex.z-dn.net/?f=V%20%3D%202000000%5C%2Ccm%5E%7B3%7D)
The largest possible volume of the box is 2000000 cubic meters.