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Alexxandr [17]
3 years ago
12

Determine which sets of lengths can form a right triangle

Mathematics
1 answer:
OLga [1]3 years ago
8 0
30,60,90 cannot make a triangle

10,24,26 can make a right triangle

6,14,18 cannot make a right triangle

I hope this helps
You might be interested in
-4 (2x + 13) + 3x = 80<br> How do you solve this out and get the answer
shusha [124]
Hey :)

x= -12

Use the distributive property to multiply −4 by 2x+13


−8x−52=3x+80
Subtract 3x from both sides
−8x−52−3x=80


Combine −8x and −3x to get −11x
−11x−52=80

Add 52 to both sides
−11x=80+52


Add 80 and 52 to get 132
−11x=132


Divide both sides by −11
x= 132/-11
​

Divide 132 by −11 to get −12
x=−12


Hope this helps :)
6 0
3 years ago
What number represents the median? <br>01.10<br>2 14<br>3.16<br>4.20<br>5.29​
Mariulka [41]
The answer is 3.16




explanation:






.
8 0
3 years ago
Read 2 more answers
Solve the equation: 3^3x-8=81 PLZ HELPPPP
pentagon [3]

Answer:

if you are solving for then it is x = 4/3

Step-by-step explanation:

8 0
3 years ago
BRAINLIEST for the correct answer!
Vladimir [108]

Answer:

answer is A

Step-by-step explanation:

(3x^{2}+5x+1) (x^{2}−2x+4)

=(3x^{2}+5x+1)(x^{2}+−2x+4)

=(3x^{2})(x^{2})+(3x^{2})(−2x)+(3x^{2})(4)+(5x)(x^{2})+(5x)(−2x)+(5x)(4)+(1)(x^{2})+(1)(−2x)+(1)(4)

=3x^{4}−6x^{3}+12x^{2}+5x^{3}−10x^{2}+20x+x^{2}−2x+4

=3x^{4} − x^{3} + 3x^{2} + 18x +4

4 0
3 years ago
Its super duper easy but im having some trouble<br> so can someone help me?
Klio2033 [76]

together = add

add the fractions

3 7/10 + 5 9/10

add the whole numbers first

3+5=8

add the fractions

7/10+9/10= 16/10

8 16/10

reduce 16/10 divide by 2

16/2= 8

10/2= 5

8 8/5

whole number changes to 9

8-5=3

denominator stays the same

9 3/5

Answer:

9 3/5

8 0
3 years ago
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