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3 years ago

(9x^3+2x^2-5x+4) - (5x^3-7x+4) Show your work.

2 answers:

8 0

9x^3 - 5x^3 = 4x^3

2x^2 doesn’t substitute with anything

-5x - (-7x) = -5x + 7x = 2x

4 - 4 = 0

Reminders

4x^3 + 2x^2 +2x

If you have have to simplify

2(2x^3 +x^2 +x)

torisob [31]3 years ago

7 0

Answer:

2x( $2x^{2}$ +x+1)

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3 years ago

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A cab company charges $4 per cab ride, plus an additional $3 per mile driven. How long is a cab ride that costs $22?

Doss [256]

Answer:

6 miles

Step-by-step explanation:

Flat fee is $4

Per mile is $3

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4 + 3m = 22

subtract 4 from both sides

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3 years ago

What is an equation of the line that passes through the point (-4,-6) and is perpendicular to the line 4x+5y=25

elixir [45]

Answer:

$y = \frac{5}{4} x - 1$

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is its gradient and c is its y-intercept.

First rewrite the equation of the given line in the form of y=mx +c.

4x+5y=25

5y= -4x +25

$y = - \frac{4}{5} x + 5$

The gradient of the given line is $- \frac{4}{5}$

The product of the gradient of perpendicular lines is -1.

$( - \frac{4}{5} )(gradient \: of \: line) = - 1 \\ gradient \: of \: line = - 1 \div ( - \frac{4}{5} ) \\ gradient \: of \: line = \frac{5}{4}$

Thus, m= $\frac{5}{4}$

$y = \frac{5}{4} x + c$

Substitute a coordinate to find c.

When x= -4, y= -6,

$- 6 = \frac{5}{4} ( - 4) + c \\ - 6 = - 5 + c \\ c = 5 - 6 \\ c = - 1$

Hence, the equation of the line is

$y = \frac{5}{4} x - 1$

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3 years ago