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kramer
3 years ago
13

What is the constant term in the expression 6x3y + 8x2 + 5x + 7? (Input a numeric value only.)

Mathematics
2 answers:
serious [3.7K]3 years ago
8 0

Answer:

7

Step-by-step explanation:

<u>Given expression:</u>

  • 6x³y + 8x² + 5x + 7

The constant is a term that has no variables. Let's verify the terms in the expression to determine which term is the constant.

Determining if 6x³y is a constant:

  • This term is not a constant because the term includes two variables (x and y).

Determining if 8x² is a constant:

  • This term is not a constant because the term includes a variable (x).

Determining if 5x is a constant:

  • This term is not a constant because the term includes a variable (x).

Determining if 7 is a constant:

  • This term is a constant because the term has no variables.

Learn more about constants: brainly.com/question/11977365

FromTheMoon [43]3 years ago
4 0

Answer:

7

Step-by-step explanation:

The constant term in an expression is the term <u>without</u> a variable.

The variables in this expression are x and y, so the constant term is 7 as this term does not have a variable.

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Jeremy can stand on one leg for 3.8 minutes. Express that time in seconds.
Salsk061 [2.6K]

Answer:

He can stand on one leg for 228 seconds.

Step-by-step explanation:

You multiply the 3.8 seconds by 60.

So, 3.8 * 60 = 228

Hope this helps :)

7 0
3 years ago
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What is the slope and y-intercept of y=2x-3
Vesnalui [34]

Answer:

slope=2x, y-intercept=-3

Step-by-step explanation:

When in slope intercept, the slope (m) is always the x (and whatever number is in front of it), and the y-intercept (b) is at the end of the equation.

6 0
3 years ago
What is -6+x-3 if x=2
kow [346]

Answer:

<h2>-7</h2>

Step-by-step explanation:

-6+x-3 \\x =2\\\\-6+2-3\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:\\-6+2=-4\\\\=-4-3\\\\=-7

6 0
4 years ago
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Please help urgent fasttt
sergeinik [125]

Answer:

  • Perimeter= l1+l2+w3+w4
  • Where l1 and l2 are equal in magnitude
  • Alike w3 and l
  • w4 are equal in magnitude
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  • Plug it in to the equation

3 0
3 years ago
8wsquared2<br><img src="https://tex.z-dn.net/?f=8w%20%7B2%20%7D%5E%7B2%7D%20%20-%2018w" id="TexFormula1" title="8w {2 }^{2} - 1
balandron [24]

{\text{Here, we have the algebraic expression}} \hfill \\ 8w \times {2^2} - 18w \hfill \\ {\text{For simplifying the expression, first we solve the exponent part,}} \hfill \\ {\text{and then the resultant will be multiply with the monomial }}18w \hfill \\ 8w \times {2^2} - 18w \hfill \\ = 8 \times w \times {2^2} - 18w \hfill \\= \left( {8 \times {2^2}} \right) \times w - 18w\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left[ {\because \,{\text{By associative law }}a \times \left( {b \times c} \right) = \left( {a \times b} \right) \times c} \right] \hfill \\   = \left( {8 \times 4} \right) \times w - 18w \hfill \\   = 32 \times w - 18w \hfill \\= 32w - 18w \hfill \\= 14w \hfill \\

4 0
4 years ago
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