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Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
<h2>○=> <u>Correct answer</u> :</h2>
of the drink is fruit juice
<h3>○=> <u>Steps to derive correct answer</u> :</h3>
Quantity of water in a drink = 650 ml
Quantity of fruit juice in a drink = 150 ml
Total quantity of both items in the drink :
Thus, the total quantity of both items in the drink = 800 ml
Let the percentage of of fruit juice in the drink be x%.
Which means :
Then, the percentage of water in the drink :
Thus, the percentage of water in the drink = 81.25%
<h3>○=> <u>Therefore</u> :</h3>
▪︎Percentage of fruit juice in the drink = 18.75%
▪︎Percentage of water in the drink = 81.75%
Answer:
2) no
3) yes
Step-by-step explanation:
i think. sorry if im wrong