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Otrada [13]
2 years ago
13

Please help me and thank you and need this before Monday

Chemistry
1 answer:
pychu [463]2 years ago
3 0

In a reaction involving sodium metal and chlorine gas, the amount of sodium metal required to react with 0.950 grams of chlorine gas would be 0.62 grams

<h3>Stoichiometric calculation</h3>

From the balanced equation of the reaction:

2Na (s) + Cl2 (g) ---------> 2NaCl (s)

The mole ratio of Na to Cl2 is 2:1.

Mole of 0.950 grams of chlorine gas = 0.950/70.906

                                                             = 0.0134 moles

Equivalent mole of Na = 0.0134 x 2 = 0.0268 moles

Mass of 0.0268 moles Na = 0.0268 x 22.99

                                           = 0.62 grams

More on stoichiometric calculations can be found here: brainly.com/question/8062886

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