The relation between the refractive index and the optical density of the material is a direct relation.
This means that the more the refractive index is, the more optically dense the material is.
Based on the above, when checking the given choices, the refractive index that represents the most optically dense material would be the largest refractive index which is:
<span>d. 2.65</span>
Answer:
The value of R and the internal resistance of the battery are 10.6 ohm and 2.45 ohm
Explanation:
Given that,
Emf of battery = 15.0 V
Voltage = 12.2 V
Power = 14.0 W
(a). We need to calculate the value of R
Using formula of power



Where, R = resistance
P = power
V = voltage
Put the value into the formula


(b). We need to calculate the internal resistance of the battery
Firstly we calculate the current
Using formula of current

Put the value of P and V into the formula


We calculate the internal resistance
Using formula of emf


Put the value into the formula


Hence, The value of R and the internal resistance of the battery are 10.6 ohm and 2.45 ohm
Answer:
If it isn't an ion it should have 35 elektrons to cancel the positivity of the nucleus.