The final velocity of object 2 is: 3 m/sec
<h3>What is the conservation of mass?</h3>
According to the rule of conservation of mass, no atoms are created or destroyed during a chemical process. Instead, the atoms combine in a variety of ways to create goods. This explains why each element has the equal amount of atoms on both sides of an equation with balanced symbols.
According to conservation of mass,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Given that,
m₁ = 50 kg
m₂ = 75 kg
u₁ = 4 m/s
u₂ = -1 m/s
v₁ = -2 m/s
v₂ = ?
Now, putting the values,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(50 × 4) + [75 × (-1)] = [50 × (-2)] + (75 × v₂)
or, 125 = -100 + 75 v₂
or, 75 v₂ = 225
or, v₂ = 3 m/sec.
To know more about velocity refer to:
brainly.com/question/80295
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We live on the troposphere
Answer:
The magnitude will be "
". The further explanation is given below.
Explanation:
Trying to determine what is usual for a rectangular loop plane,
⇒ 
Magnetic moment is given as:
μ = 
On putting the values in the above formula, we get
μ = ![(5.5A)[(0.3m)(0.4m)][(Cos35^{\circ})(\hat{i})+(Sin35^{\circ})(-\hat{k})]](https://tex.z-dn.net/?f=%285.5A%29%5B%280.3m%29%280.4m%29%5D%5B%28Cos35%5E%7B%5Ccirc%7D%29%28%5Chat%7Bi%7D%29%2B%28Sin35%5E%7B%5Ccirc%7D%29%28-%5Chat%7Bk%7D%29%5D)
= ![0.66 Am^2[(Cos35^{\circ})(\hat{i})+(Sin35^{\circ})(\hat{k})]](https://tex.z-dn.net/?f=0.66%20Am%5E2%5B%28Cos35%5E%7B%5Ccirc%7D%29%28%5Chat%7Bi%7D%29%2B%28Sin35%5E%7B%5Ccirc%7D%29%28%5Chat%7Bk%7D%29%5D)
Now the external vector-shaped torque seems to be:
Magnitude,

On putting the values in the above formula, we get
⇒ ![\sigma=[(0.06Am^2)(Cos35^{\circ}(-\hat{i})+Sin35^{\circ}(-\hat{k})]\times (2.9T)(-\hat{i})](https://tex.z-dn.net/?f=%5Csigma%3D%5B%280.06Am%5E2%29%28Cos35%5E%7B%5Ccirc%7D%28-%5Chat%7Bi%7D%29%2BSin35%5E%7B%5Ccirc%7D%28-%5Chat%7Bk%7D%29%5D%5Ctimes%20%282.9T%29%28-%5Chat%7Bi%7D%29)
⇒ 
⇒ 
⇒ 
Answer:
s = 2.16 x 10¹¹ m
Explanation:
Since, the waves travelling from Earth to the Mars rover are electromagnetic. Therefore, there speed must be equal to the speed of light. So, from the equation given below:
s = vt
where,
s = the distance between Earth and Mars = ?
v = speed of the wave = speed of light = 3 x 10⁸ m/s
t = time taken by the radio signals to reach the rover from Earth
t = (12 min)(60 s/1 min) = 720 s
Therefore,
s = (3 x 10⁸ m/s)(720 s)
<u>s = 2.16 x 10¹¹ m</u>