Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2
−2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n} ba =nm
\ l^2 = ab - mnl 2=ab-mm
A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=
4R
abc
- R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
Answer: false
Step-by-step explanation:
Answer:
Step-by-step explanation:
The odd numbers.
Suppose you have 31 and 27 when you add these two together, you get 58 which is not an odd number.
If you need a more mathematical proof, you could do it this way.
2x+1
2x is even. Anything multiplied by 2 is even. When you add 1 you get an odd number
So continue on
2y + 1 is the other number.
2x + 1 + 2y + 1 = 2(x + y) + 2
2 (x + y ) is even. When you add 2 to it, nothing changes. The result is still even.
Answer:
C) 100 m^2
Step-by-step explanation:
Area of a trapezoid= h*[(b1+b2)/2]
h=10
b1=8
b2=12
Therefore:
A=10*[(8+12)/2]
A=10*(20/2)
A=10*10
A=100
So the area of the trapezoid is 100 m^2
