Answer:
The product of the reaction between a ketone and an alcohol is initially a hemiketal which yields a ketal on further reaction with another alcohol molecule.
The structure is found in the attachment.
Explanation:
This reaction is a <em>nucleophilic addition to the carbonyl group</em>. In organic chemistry, <em>a nucleophilic addition reaction is an addition reaction where a chemical compound with an electron-deficient or </em><em>electrophilic</em><em> double or triple bond, a pi (π) bond, reacts with electron-rich reactant, termed a </em><em>nucleophile</em><em>, with the elimination of the double bond and creation of two new single, or sigma (σ), bonds.</em>
In the reaction between a ketone and an alcohol, the <em>carbonyl</em> group of the ketone serves as the <em>electrophile</em> while the <em>hydroxyl</em> group of the alcohol is the <em>nucleophile</em>. The first product is known as a hemiketal because a single alcohol group has been aded to the carbonyl group of the ketone. Further nucleophilic additon of an alcohol group initiated by the presence of an acid e.g hydrochloric acid, results in the formation of a ketal which has two alcohol group added to the original ketone.
Explanation:
We know that relation between and is as follows.
= 14
As it is given that is 8.18. Therefore, calculate the value of as follows.
= 14
= 14
= 14 - 8.18
= 5.82
Similarly, as value of pH is given as 7.18. Therefore, value of pOH will be as follows.
pH + pOH = 14
7.18 + pOH = 14
pOH = 6.82
Let us take that B represents the enzyme. Hence, its reaction with proton will be as follows.
(protonated active enzyme)
Hence, pOH =
6.82 = 5.82 +
= 10
Therefore, percentage of active enzyme = % =
% = 90.9%
Thus, we can conclude that 90.9% is the percentage of the enzyme which is active in a buffer at pH 7.18.
Answer:
83.69 gm
Explanation:
molar weight of N2 = 28
Find the number of moles then multiply by this
1.8 x10^24/ (6.022x10^23) * 28 =83.69 gm
The answer is C. Here is the work:
<span>Moles=molarity * volume
2.5 * 0.5 = 1.25mols of NaCI
Mm of NaCI= 58.442468/mol
Multiply the moles by the Mm and you get the grams
1.25 * 58.442468 =73.1g
</span>
1. 9
2. 13
to find the atomic mass you add the protons and neutrons
there are the same amount of protons as electrons in every atom