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Gre4nikov [31]
3 years ago
13

Spell out full name of compound

Chemistry
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Answer:

3-methyl-pentan-2-ol.

or

3-methyl-2-pentanol.

Explanation:

Hello,

In this case, such mocule is a branched alcohol since one commences numbering the chain by the right side of it, thus, we find a hydroxile and a methyl at the second and third carbons repectively. In this manner, the full name of the compound is:

3-methyl-pentan-2-ol.

or

3-methyl-2-pentanol.

As the main functional group is the hydroxide which characterizes the compound as an alcohol.

Best regards.

Margarita [4]3 years ago
7 0
Hydroxide is the full name of the compound.

Hope this Helped!

;D
Brainliest??
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Afina-wow [57]

Answer:

0.373 moles of ammonium carbonate

Explanation:

To solve this question we must find the molar mass of ammonium carbonate. With the molar mass and the mass we can find its moles, as follows:

(NH₄)₂CO₃ contains: 2 moles N, 8 moles H, 1 mole C, 3 moles O. Molar mass:

2N = 14.0g/mol*2 = 28.0

8H = 1.0g/mol*8 = 8.0

1C = 12.0g/mol*1 = 12.0

3O = 16.0g/mol*3 = 48.0

Molar mass: 28.0 + 8.0 + 12.0 + 48.0 = 96.0g/mol

The moles of ammonium carbonate in 35.8g are:

35.8g * (1mol / 96.0g) =

<h3>0.373 moles of ammonium carbonate</h3>
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3 years ago
Iodine chloride, ICl, can be made by the following reaction between iodine, I2, potassium iodate, KIO3, and hydrochloric acid.
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The balanced chemical reaction is:

<span>2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O 
</span>
We are given the amount of the product to be produced from the reaction. This will be the starting point of our calculations.

28.6 g ICl (1 mol / 162.35 g ICl ) ( 2 mol I2 / 5 mol ICl ) ( 253.81 g I2 / 1 mol I2 ) = 17.88 g I2
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The compound zinc fluoride is a strong electrolyte. write the transformation that occurs when solid zinc fluoride dissolves in w
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Help pls <br> is this direct, constant, indirect, or cycling?
IRISSAK [1]

Answer:

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Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide. Ca) + H2O --&gt; Ca(OH)2 In a particular
mars1129 [50]

Answer:

Percent yield = 92.5%

Explanation:

The question asks for the percent yield which can be defined as:

\frac{actual yield}{theoretical yield} .100

Where the actual yield is <em>how much product was obtained</em>, in this case 6.11 g of Ca(OH)₂, and the theoretical yield is <em>how much product could be obtained with the given reactants theoretically</em>, that is if the reaction would work perfectly. So we need to calculate first the theoretical yield.

1. First lets write the chemical equation reaction correctly and check that it is balanced:

CaO + H₂O → Ca(OH)₂

2. Calculate the amount of product Ca(OH)₂ that can be obtained with the given reactants (theoretical yield), which are 5.00g of CaO and excess of water. So the amount of CaO will determined how much Ca(OH)₂ we can obtained.

For this we'll use the molar ratio between CaO and Ca(OH)₂ which we see it is 1:1. For every mol of CaO we'll obtain a mol of Ca(OH)₂. So lets convert the 5.00 g of CaO to moles:

 Molar Mass of CaO: 40.078 + 15.999 = 56.077 g/mol

 moles of CaO = 5.00 g / 56.077 g/mol = 0.08916 moles

As we said before from the molar ratio moles of Ca(OH)₂ = moles of CaO

So the moles of Ca(OH)₂ that can be obtained are 56.077 g/mol

We need to convert this value to grams:

 Molar Mass of Ca(OH)₂ = 40.078 + (15.999 + 1.008)*2 = 74.092 g/mol

Theoretical yield of Ca(OH)₂ = 0.08916 moles x 74.092 g/mol = 6.606 g

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\frac{actual yield}{theoretical yield} .100

Percent yield = (6.11 g / 6.606g) x 100 = 92.5 %

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