Answer:
NH4Cl, NaCl, Ba(OH)2, NaOH
Explanation:
NH4Cl is an acidic salt formed by the neutralization of a strong acid (HCl) with a weak base (NH3). Hence, it will habe a PH<7 (the lowest PH).
NaCl is a neutral salt,formed by neutralization of a strong acid (HCl) with a strong base (NaOH). Hence, it will have a PH of 7.
Ba(OH)2 is a weak base. Therefore, it will have a PH between 8 and 10.
NaOh meanwhile, is a strong base. Therefore, it will have a PH between 10 to 13.
Hence, we have
NH4Cl < NaCl < Ba(OH)2 < NaOH
Answer:
Chemical symbols are used to standardize the 'language of chemistry' and to identify elements and atoms in a chemical formula easily. Chemical symbols consist of one or two letters, most often derived from the name of the element.
Explanation:
Answer:
false
Explanation:
Weathering describes the breaking down or dissolving of rocks and minerals on the surface of the Earth. Water, ice, acids, salts, plants, animals, and changes in temperature are all agents of weathering.
Answer:
Explanation:
1. find the molar mass (amu) of each element and add them to get the whole molar mass.
2. divide the 1 element molar mass with the whole molar mass
3. multiple by 100 and that gives you the % composition.
<h2><u><em>56-57: NaCl</em></u></h2>
1. Na(22.99amu) + Cl (35.453amu)=58.443
2(Na):
= .393
2(Cl):
= .607
3(Na): .393 * 100=39.3%
3(Cl): .607 * 100= 60.7%
<h2><u>58-60 </u>

<u /></h2>
1. K: (39.098)(2)=78.196
_ C: (12.011)(1)= 12.011
_O: (15.99)(3) = 47.997
78.196+12.011+47.997= 138.204
2:K:
= .566 <u>Step </u>3: (.566)(100)= 56.6%
2: C:
= .087 <u>Step 3</u>: (.087)(100)= 8.7%
2: O:
= .347 <u>Step 3</u>: (.347)(100) = 34.7%
<h2>
61-62 
</h2>
1. Fe (55.845)(3)= 167.535
_ O (15.999)(4) = 63.996
167.535+63.996=231.531
2: Fe:
= .724 Step 3: (.724)(100)= 72.4%
2: O :
= .276 Step 3: (.276)(100) = 27.6%
<h2>63-65

</h2>
1.
C(12.011*3)=36.033
H(1.008*5)=5.04 + (1.008*3)=3.024 so its 8.064
O(15.999*3)=47.997
add them: 92.094
2: C:
= .391 Step 3: (.391)(100) = 39.1%
2: H:
= .088 step 3: (.088)(100) = 8.8%
2: O:
= .521 step 3: (.521)(100) = 52.1%