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Gre4nikov [31]
3 years ago
13

Spell out full name of compound

Chemistry
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Answer:

3-methyl-pentan-2-ol.

or

3-methyl-2-pentanol.

Explanation:

Hello,

In this case, such mocule is a branched alcohol since one commences numbering the chain by the right side of it, thus, we find a hydroxile and a methyl at the second and third carbons repectively. In this manner, the full name of the compound is:

3-methyl-pentan-2-ol.

or

3-methyl-2-pentanol.

As the main functional group is the hydroxide which characterizes the compound as an alcohol.

Best regards.

Margarita [4]3 years ago
7 0
Hydroxide is the full name of the compound.

Hope this Helped!

;D
Brainliest??
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Solution (A) contains 0.01 M of NH4Cl; solution
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Answer:

NH4Cl, NaCl, Ba(OH)2, NaOH

Explanation:

NH4Cl is an acidic salt formed by the neutralization of a strong acid (HCl) with a weak base (NH3). Hence, it will habe a PH<7 (the lowest PH).

NaCl is a neutral salt,formed by neutralization of a strong acid (HCl) with a strong base (NaOH). Hence, it will have a PH of 7.

Ba(OH)2 is a weak base. Therefore, it will have a PH between 8 and 10.

NaOh meanwhile, is a strong base. Therefore, it will have a PH between 10 to 13.

Hence, we have

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Why should we never change a symbol in chemistry?
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Answer:

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Plants and animals can build up or break down rock by increasing weathering, erosion, and
alexgriva [62]

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3 years ago
PLEASE HELP!! I REALLY NEED HELP
Allushta [10]

Answer:

Explanation:

1. find the molar mass (amu) of each element and add them to get the whole molar mass.

2. divide the 1 element molar mass with the whole molar mass

3. multiple by 100 and that gives you the % composition.

<h2><u><em>56-57: NaCl</em></u></h2>

1. Na(22.99amu) + Cl (35.453amu)=58.443

2(Na):   \frac{22.99}{58.443} = .393

2(Cl): \frac{35.453}{58.443}= .607

3(Na): .393 * 100=39.3%

3(Cl): .607 * 100= 60.7%

<h2><u>58-60 </u>K_{2} CO_{3}<u /></h2>

1. K: (39.098)(2)=78.196

_ C: (12.011)(1)= 12.011

_O: (15.99)(3) = 47.997

78.196+12.011+47.997= 138.204

2:K: \frac{78.196}{138.204}= .566 <u>Step </u>3: (.566)(100)= 56.6%

2: C: \frac{12.011}{138.204}= .087 <u>Step 3</u>: (.087)(100)= 8.7%

2: O: \frac{47.997}{138.204}= .347 <u>Step 3</u>: (.347)(100) = 34.7%

<h2>61-62 Fe_{3} O_{4}</h2>

1. Fe (55.845)(3)= 167.535

_ O (15.999)(4) = 63.996

167.535+63.996=231.531

2: Fe: \frac{167.535}{231.531}= .724 Step 3: (.724)(100)= 72.4%

2: O : \frac{63.996}{231.531}= .276 Step 3: (.276)(100) = 27.6%

<h2>63-65 C_{3}H_{5}(OH)_{3}</h2>

1.

C(12.011*3)=36.033

H(1.008*5)=5.04 + (1.008*3)=3.024 so its 8.064

O(15.999*3)=47.997

add them: 92.094

2: C: \frac{36.033}{92.094}= .391 Step 3: (.391)(100) = 39.1%

2: H: \frac{8.064}{92.094}= .088 step 3: (.088)(100) = 8.8%

2: O: \frac{47.997}{92.094} = .521 step 3: (.521)(100) = 52.1%

3 0
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