Answer:
Q = 306 kJ
Explanation:
Given that,
Mass, m = 60 kg
Specific heat, c = 1020 J/kg°C
The temperature changes from 20°C to 25°C.
Let Q be the change in thermal energy. The formula for the heat released is given by :
Put all the values,
So, 306 kJ is the change in thermal energy.
Mole =
Mass of Radium Hydroxide = 987g
Molar Mass of
= ((226) + (2 * 16) + (2 * 1))
= 260 g / mol
∴ Moles of <span>
= </span>
= 3.796 mols
Use the equation d=m/v
your mass or "m" is 78 g
your volume or "v" is 60mL
if you plug those values into the equation it will look like this:
d=78/60
d=1.3g/mL should be what you come up with
Answer:
I
Explanation:
Among the halogens given in this problem, iodine has the lowest attraction for electrons.
This property is known as electronegativity.
Electronegativity is expressed as the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.
- As you go down the periodic group the electronegativity decreases.
- The most electronegative element on the periodic table is fluorine.
- Down the group, iodine is the least electronegative
- This is due to the large size of its atom.
Answer:
B) 0.230 M
Explanation:
The first step is to <u>balance the reaction</u> between the Ferrous ion and the permanganate ion:
Then we have to <u>calculate the moles</u> of 
:
Then using the <u>molar ratio</u> we can find the moles of 
:
Finally we can calculate the molarity:
