All categories

3 years ago

Which of the following is true about two neutral atoms of the element gold?

Chemistry

2 answers:

Nuetrik [128]3 years ago

7 0

C is correct on this problem

alexandr402 [8]3 years ago

7 0

Answer: Option (c) is the correct answer.

Explanation:

Each element is made up of same type of atoms which cannot be further divided into simpler substances.

For example, a piece of zinc metal will only contains atoms of zinc and no other element.

Since, these atoms are the same as the element itself. Hence, the element still retain its properties because there no other different element is present in it.

Thus, we can conclude that the statement both have the same properties, is true about two neutral atoms of the element gold.

You might be interested in

Which part of the mantle is still a solid but flows like a thick, heavy liquid?

marusya05 [52]

Hello!

Your answer is A, asthenosphere

The asthenosphere is a part of the mantle. It helps move the plates in the Earth.

It is below the lithosphere, between 80 and 200 km below the surface.

Therfore, the asthenosphere is the part of the mantle that is still a solid but flows like a thick, heavy liquid.

Hope this helps!

Have a great day!

3 0

3 years ago

Read 2 more answers

Calculate the percent ionization of propionic acid (C2H5COOH) in solutions of each of the following concentrations (Ka is given

tekilochka [14]

Answer:

a) = 0.704%

b) = 1.30%

c) = 2.60%

Explanation:

Given that:

$K_a$ = $1.34*10^{-5$

For Part A; where Concentration of A = 0.270 M

Percentage Ionization(∝) $\alpha = \sqrt{\frac{K_a}{C} }$

$\alpha = \sqrt{\frac{1.34*10^{-5}}{0.270} }$

$\alpha = \sqrt{4.9629*10^{-5}}$

$\alpha = 7.044*10^{-3$

percentage% (∝) = $7.044*10^{-3}*100$

= 0.704%

For Part B; where Concentration of B = $7.84*10^{-2$ M

$\alpha = \sqrt{\frac{1.34*10^{-5}}{7.84*10^{-2}} }$

$\alpha = \sqrt{1.709*10^{-4} }$

$\alpha = 0.0130\\$

percentage% (∝) = 0.0130 × 100%

= 1.30%

For Part C; where Concentration of C= $1.92*10^{-2} M$

$\alpha = \sqrt{\frac{1.34*10^{-5}}{1.97*10^{-2}} }$

$\alpha = \sqrt{6.802*10^{-4}}$

$\alpha =0.02608$

percentage% (∝) = 0.02608 × 100%

= 2.60%

7 0

3 years ago

In a particular titration experiment a 30.0 ml sample of an unknown hcl solution required 25.0 ml of 0.200 m naoh for the end po

Nikitich [7]

The balanced equation for the acid base reaction is as follows
NaOH + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
the number of NaOH moles reacted - 0.200 mol/L x 0.0250 L = 0.005 mol
according to molar ratio
number of NaOH moles reacted = number of HCl moles reacted
therefore number of HCl moles - 0.005 mol
volume of 30.0 mL contains 0.005 mol
therefore 1000 mL contains - 0.005 mol / 0.030 L = 0.167 M
concentration of HCl is 0.167 M

5 0

3 years ago

What is the definition of toxicity?

larisa [96]

Answer:

The level of toxins in solutions

4 0

2 years ago

Read 2 more answers

ILL GIVE BRAILNEST!!!!! PLZ HELP ME FAST

NemiM [27]

Multiple states of matter - mixture
Same state of matter - pure
Separated physically- mixture
Consistent properties - pure
Can’t be separated- pure
Can’t be a single element - mixture

3 0

3 years ago