Answer:
m<NQS = 32°
Step-by-step explanation:
Given:
m<BQS = 80°
m<BQN = 48°
Required:
m<NQS
SOLUTION:
Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.
Therefore:
m<BQN + m<NQS = m<BQS (angle addition postulate)
48° + m<NQS = 80° (substitution)
m<NQS = 80 - 48° (Subtraction of 48 from each side)
m<NQS = 32°
Answer:
384.3
Step-by-step explanation:
Answer:
Dimensions:
Perimiter:
Minimum perimeter: [16,16]
Step-by-step explanation:
This is a problem of optimization with constraints.
We can define the rectangle with two sides of size "a" and two sides of size "b".
The area of the rectangle can be defined then as:
This is the constraint.
To simplify and as we have only one constraint and two variables, we can express a in function of b as:
The function we want to optimize is the diameter.
We can express the diameter as:
To optimize we can derive the function and equal to zero.
The minimum perimiter happens when both sides are of size 16 (a square).
Answer:
x = 17
Step-by-step explanation:
For the parallelogram to be a rhombus then then the diagonal must bisect the given angle, thus
3x - 11 = x + 23 ( subtract x from both sides )
2x - 11 = 23 ( add 1 to both sides )
2x = 34 ( divide both sides by 2 )
x = 17
Answer:
post the whole thing
Step-by-step explanation:
then ill do it