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ehidna [41]
2 years ago
13

A car with a mass of 1,500 kg broke down on the side of the road. How much force will be required

Mathematics
1 answer:
Schach [20]2 years ago
7 0

Answer:

the answer is 4,500kgm/s2

Step-by-step explanation:

force= mass × acceleration

f = 1500 \times 3 \\  = 4500kgm {s}^{ - 2}

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Write a polynomial equation with integer coefficients that has the given roots x=1, x=-4
Gekata [30.6K]
(x -1)(x +4) = 0

x² +3x -4 = 0 . . . . . . probably the form you're looking for
7 0
3 years ago
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Solution for x+4 is equal to 10​
Mars2501 [29]
The answer is x=6. This is because 6+4 equals 10
8 0
3 years ago
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Please help! Will mark brainlyest. :)
Elden [556K]

Answer:

48

Step-by-step explanation:

base times hight times times 1/2

24X4X1/2

7 0
1 year ago
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Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
Determine whether the graphs of y=8x+5 and -y=-8x-5 are parallel ,perpendicular,coincident , or none of these.
PolarNik [594]

Answer:

Below

Step-by-step explanation:

The equations are:

● y = 8x + 5

● -y = -8x + 5 => y = 8x - 5

Both lines have the same slope wich means that they are parallel

5 0
2 years ago
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