A car with a mass of 1,500 kg broke down on the side of the road. How much force will be required

What is 4 (5×1÷20) because I dont know lol

Whitepunk [10]

Well first we need to do whatever is in the parentheses, which in this case is: (5x1/20)

Following the order of operations (PEMDAS) we start with the multiplication, which is (5x1). We know that 5x1=5, so now we can move on to the division:

5/20, which is equal to 0.25

So now that we know the answer to the equation in the parentheses is 0.25, we can solve the whole equation.

Here is the equation simplified:

4 (0.25)

Because there is now operation indicated between the 4 and the parentheses, we can assume that multiplication is implied, so the final equation is as follows:

4x0.25=1

The final answer is: 1

Hope this helps!

4 0

3 years ago

John works two jobs. As a security guard he earns $8.50 per hour. As a landscaper he earns $14 per hour. One week John worked a

Rashid [163]

Answer:

John work as a security guard job 27 hours and as a landscaper 33 hours.

Step-by-step explanation:

Given:

John works two jobs.

As a security guard he earns $8.50 per hour and as a landscaper he earns $14 per hour.

One week John worked a total of 60 hours and earned $691.50.

Now, to find hours he work at each job.

Let the job of security guard be $x$ hours.

And the job of landscaper be $y$ hours.

So, the total hours John worked in a week:

$x+y=60.$

⇒ $y=60-x.$ ............( 1 )

Now, the money earned by John in a week:

$8.50x+14y=691.50$

Putting the equation ( 1 ) in the place of $y$ :

⇒ $8.50x+14(60-x)=691.50$

⇒ $8.50x+840-14x=691.50$

Moving variables on one side and the other we get:

⇒ $840-691.50=14 x-8.50x$

⇒ $148.50=5.50x$

Dividing both sides by 5.50 we get:

⇒ $27=x$

As a security guard job he worked 27 hours.

Putting the value of in $x$ equation ( 1 ) we get:

$y=60-27$

⇒ $y=33.$

As a landscaper he worked 33 hours.

Therefore, John work as a security guard job 27 hours and as a landscaper 33 hours.

5 0

3 years ago

Three people play a game on each spinner in the previos problem.

arlik [135]

Answer:

Step-by-step explanation:

All other things being equal, spinner A is fine. It is a fair spinner.

Spinner B is not fair. Players 1 and 3 have only 1 number each. Player 2 on the other hand, has 2 numbers that work for him. If player 2 puts in two dollars and players 1 and 3 one dollar each, that should even up the odds. Now you want it just to be fair. So I think player 2 has to put up 2 dollars and players 1 and 3 each put up one. The pot is 4 dollars each time it is played.

Spinner 3 is not fair either. Player one has 2 chances. Player 2 has 3 chances and player 3 has but one chance. There are 6 chances in all. Player 1 should put up 2 dollars to play player 1 should put up 3 dollars and player 1 should put up 1 dollar.

5 0

3 years ago

Brayden has a triangular flag hanging in his room. What is the area of the flag? *

elena-s [515]

Answer:

if you want the base and the height you have to give me number or do you want the formula ?

3 0

3 years ago

a. 0.98 – 0.053 b. 0.67 – 0.4 c. 0.3 – 0.002 d. 3.2 – .789 e. 6.53 – 4.298 f. 6 – 4.32 g. 7 – 3.574 h. 4.83 – 1.8 i. 3.7 – 1.8 j

Pavlova-9 [17]

a. 0.927

We have:

0.98 – 0.053

We can re-write it as:

0. 9 8 0 -

0. 0 5 3

Moving digits to the right:

0. 9 7 10 -

0. 0 5 3

Digit-per-digit subtraction:

0. 9 2 7

b. 0.27

We have:

0.67 – 0.4

We can re-write it as:

0. 6 7 -

0. 4 0

Digit-per-digit subtraction:

0. 2 7

c. 0.298

We have:

0.3 – 0.002

We can re-write it as:

0. 3 0 0 -

0. 0 0 2

Moving digits to the right:

0. 2 10 0 -

0. 0 0 2

Again:

0. 2 9 10 -

0. 0 0 2

Digit-per-digit subtraction:

0. 2 9 8

d. 2.411

We have:

3.2 – .789

We can re-write it as:

3. 2 0 0 -

0. 7 8 9

We need to rewrite the first term by moving digits to the right several times:

3. 2 0 0 = 2. 12 0 0 = 2. 11 10 0 = 2. 11 9 10

So now we have:

2. 11 9 10 -

0. 7 8 9

Digit-per-digit subtraction:

2. 4 1 1

e. 2.232

We have:

6.53 – 4.298

We can re-write it as:

6. 5 3 0 -

4. 2 9 8

We need to rewrite the first term by moving digits to the right several times:

6. 5 3 0 = 6. 5 2 10 = 6. 4 12 10

So now we have:

6. 4 12 10 -

4. 2 9 8

Digit-per-digit subtraction:

2. 2 3 2

f. 1.68

We have:

6 – 4.32

We can re-write it as:

6. 0 0 -

4. 3 2

We need to rewrite the first term by moving digits to the right several times:

6. 0 0 = 5. 10 0 = 5. 9 10

So now we have:

5. 9 10 -

4. 3 2

Digit-per-digit subtraction:

1. 6 8

g. 4.426

We have:

7 – 3.574

We can re-write it as:

7. 0 0 0 -

3. 5 7 4

We need to rewrite the first term by moving digits to the right several times:

7. 0 0 0 = 6. 10 0 0 = 6. 9 10 0 = 6. 9 9 10

So now we have:

6. 9 9 10 -

3. 5 7 4 =

Digit-per-digit subtraction:

3. 4 2 6

h. 3.03

We have:

4.83 – 1.8

We can re-write it as:

4. 8 3 -

1. 8 0

We can immediately do the digit-per-digit subtraction:

3. 0 3

i. 2.9

We have:

3.7 – 1.8

We can re-write it as:

3. 7 -

1. 8

We need to rewrite the first term by moving digits to the right:

3. 7 = 2. 17

So now we have:

2. 17 -

1. 8 =

Digit-per-digit subtraction:

2. 9

j. 4.538

We have:

16.17 – 11.632

We can re-write it as:

1 6 . 1 7 0 -

1 1 . 6 3 2

We need to rewrite the first term by moving digits to the right:

1 6. 1 7 0 = 1 6. 1 6 10 = 1 5. 11 6 10

So now we have:

1 5. 11 6 10 -

1 1. 6 3 2 =

Digit-per-digit subtraction:

0 4. 5 3 8

3 0

3 years ago