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jonny [76]
2 years ago
15

What is the decimal for 4/100? What is the Answer

Mathematics
2 answers:
Zarrin [17]2 years ago
8 0

Simply just take 4 divided by 100 -> 4 : 100 = 0.04

soldier1979 [14.2K]2 years ago
6 0

Answer:

0.04

Step-by-step explanation:

Have a nice day!

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How long is the segment from (-5, 2) to (-5,-8)?​
Pavel [41]

Answer:

10

Step-by-step explanation:

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \
Kisachek [45]

Answer:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2

Step-by-step explanation:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} = \ ?

We can use Part I of the Fundamental Theorem of Calculus:

  • \displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

  • \displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt}\  = -\int\limits^a_b \text{f(t) dt}

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

  • \displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx}  \int\limits^{x^2}_0 t^2+1 \text{ dt}  

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

  • \displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]
  • where u represents any function other than a variable

For the first term, replace \text{t} with 2x, and apply the chain rule to the function. Do the same for the second term; replace

  • \displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)  

Simplify the expression by distributing 2 and 2x inside their respective parentheses.

  • [-(8x^2 +2)] + (2x^5 + 2x)
  • -8x^2 -2 + 2x^5 + 2x

Rearrange the terms to be in order from the highest degree to the lowest degree.

  • \displaystyle2x^5-8x^2+2x-2

This is the derivative of the given integral, and thus the solution to the problem.

6 0
2 years ago
A disc jockey has 20 songs to choose from and can only play 8 in the next half hour. how many different playlists are possible?
motikmotik

This problem is a combination problem since it did not indicate that there is a specified order of songs to be played. The type of combination problem is without repetition. Thus the working equation would be n!/r!(n-r)! wherein n is the total number of songs to choose from and r is the number of songs you can choose at a given time. The answer would be 125970. 

3 0
3 years ago
Read 2 more answers
The line segment EF has a midpoint with coordinates M (-2,2). Use the formula to find the coordinates of the other endpoint give
Makovka662 [10]

Answer:

The answer to your question is:   F = (-6, -4)

Step-by-step explanation:

Segment = EF

mpM = (-2, 2)

first point = E = (2, 8)

second point = F = (x, y)

Formula

      Xmp = (x1 + x2) / 2                         Ymp = (y1 + y2) / 2

      x2 = 2xmp - x1                                y2 = 2ymp - y1

Process

     x2 = 2(-2) - 2                                   y2 = 2(2) - 8

     x2 = -4 - 2                                       y2 = 4 - 8

     x2 = -6                                            y2 = -4

                     F = (-6, -4)

8 0
2 years ago
A water tank has 1,500 liters of water. It has a leak, losing 4 liters per minute. At the same time, a second tank has 300 liter
Darina [25.2K]

Let t be the number of minutes.

The first tank starts with 1500 liters, and loses 4 liters per minute, so after t minutes there will be

1500-4t

liters of water.

The second tank is filled at 6 liters per second, i.e.

6\times 60=360 liters per minute.

So, there will be

300+360t

liters of water in the second tank after t minutes.

The two quantities will be equal when

1500-4t=300+360t \iff 1200=364t \iff t=\dfrac{1200}{364}\approx 3.3

so, approximately, after 3.3 minutes.

4 0
3 years ago
Read 2 more answers
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