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antiseptic1488 [7]
3 years ago
6

Y={1 if x is rational 0 if x is irrational How would you describe it's graph?

Mathematics
1 answer:
Setler [38]3 years ago
6 0

The set of rational plus irrational numbers equals ALL REAL NUMBERS


Yes, it is a function because every x-value maps into only one y-value. In other words, because rational and irrational are mutually exclusive, x does not map into both 0 and 1


Domain is all real numbers.


Range is 0 or 1


y-intercept happens when x=0, so that is a rational number and y = 1


There are an infinite number of x-intercepts. Every irrational number is an x-intercept


Neither even or odd because it is not symmetric with either the y-axis or the origin.


The graph jumps between y=0 and y=1


Hope that helps Answer:


Step-by-step explanation:


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Find the cost of painting a cubical block of side length 3.2 cm, if painting costs $5 per cm2.
SashulF [63]
<h3><u>Answer</u>:- </h3>

\longrightarrow \sf \$ \: 307.2

<h3><u>Solution:-</u></h3>

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

\green{ \underline { \boxed{ \sf{Surface \: area  \:of  \:Cube = 6a^2}}}}

  • <u>where a is side of the cube </u>

\begin{gathered}\\\quad \sf Surface \: area  \:of  \:Cube = 6\times(3.2)^2  \\\end{gathered}

\begin{gathered}\\\implies \quad \sf  6\times 3.2\times3.2   \\\end{gathered}

\begin{gathered}\\\implies \quad \sf  61.44 cm^2  \\\end{gathered}

Now,

\maltese \sf Cost  \:of  \:painting \: 1 \: cm² = \$ 5

\sf Cost \: of \: painting \: 61.44  \:cm²=61.44×5

\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2

\leadstoThus it would cost $ 307.2 to paint the entire cubical block.

3 0
3 years ago
Given: P is a point on the perpendicular bisector, I of MN.<br> Prove: PM = PN
Hatshy [7]

Answer:

Step-by-step explanation:

I can't make specific statements about the proof because the midpoint is missing.

Givens

There are two right angles created by where the perpendicular bisector meats MN. Both are 90 degrees.

MN is bisected by the point on MN where the perpendicular meets MN

The Perpendicular Bisector is is common to both triangles.

Therefore the two triangles are congruent by SAS

PM = PN                Parts contained in Congruent triangles are congruent.

5 0
3 years ago
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Vera_Pavlovna [14]

Answer:

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Step-by-step explanation:

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Taking the square root of each side

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l = 5w = 5*6 = 30

The perimeter is

P = 2(l+w)

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OLga [1]

The last choice is the right answer. Curves do not have a constant rate of change.

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Marina86 [1]

Answer:

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