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love history [14]
2 years ago
9

Find the area of this circle. Use 3.14 for a 11 ft The area of the circle is about ft2. (Round to the nearest hundredth as neede

d.)​

Mathematics
1 answer:
Nutka1998 [239]2 years ago
5 0

Answer:

  • <u>Area of circle is 379.94 feet²</u>

Step-by-step explanation:

<u>Given:</u><u> </u>

  • Radius of circle = 11 feet

<u>To </u><u>Find:</u><u> </u>

  • Area of circle.

<u>Solution</u>:

Here given that radius of circle is 11 feet. Using the formula of area of circle we will get the required area of circle

  • Area of circle = πr²

<u>On substituting the required values: </u>

Area = 3.14 × (11)²

Area = 3.14 × 121

Area = 379.94 feet²

Hence,

  • <u>Area of circle is 379.94 feet²</u>
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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

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The pattern of the normalized differential equation can be represented as:

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This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

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q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

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Hence, one (1) of them is non-analytical at x = 2.

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3 years ago
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at least 2 tails means 2 or 3 t in the list item :

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