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fenix001 [56]
2 years ago
13

Solve

Chemistry
1 answer:
stiv31 [10]2 years ago
7 0

The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated using the following Charle's law equation:

V1/T1 = V2/T2

Where;

  • T1 = initial temperature
  • T2 = final temperature
  • V1 = initial volume
  • V2 = final volume

  • V1 = 9L
  • V2 = ?
  • T1 = 325K
  • T2 = 450K

9/325 = V2/450

325V2 = 4050

V2 = 4050/325

V2 = 12.46L

Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

Learn more about volume at: brainly.com/question/2817451

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Answer:

\boxed {\boxed {\sf D. \ 152 \ L}}

Explanation:

Any gas at standard temperature and pressure (STP) has a volume of 22.4 liters per mole or 22.4 L/mol. We can create a proportion with this value.

\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}

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6.8 \ mol \ Kr *\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}

The units of moles of krypton will cancel.

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The denominator of 1 can be ignored, so this becomes a simple multiplication problem.

68 * 22.4 \ L \ Kr

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If we round to the nearest whole number, the 3 in the tenths place tells us to leave the 2 in the ones place.

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What is the SI unit for volume?
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How many molecules are in 49.0 g of H2SO4? Answer in units of molec.
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= 3.01× 10^{23} molecules.

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