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natulia [17]
3 years ago
9

Draw it draw lewis dot structures for each hypothetical molecule shown below, using the correct number of valence electrons for

each atom. determine which molecule makes sense because each atom has a complete valence shell and each bond has the correct number of electrons. explain what makes the other molecules nonsensical, considering the num- ber of bonds each type of atom can make

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
6 0

The first molecule is a sensible molecule having complete octet of each atom such as C, H and O whereas the second molecule having hydrogen present between the aldehyde and methyl group and thus showing hydrogen is making bond with aldehyde and methyl as well which is not possible because hydrogen only having one electron in its octet due to which it can only form a single bond by sharing its valence electron.

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Name the source of lactose and name the type of enzyme that is required to digest it
skelet666 [1.2K]

Answer:

Lactose is found in animal milk is lactase is the enzyme that is required to digest it.

Explanation:

Lactose is a disaccharide made of glucose and galactose units. This sugar is naturally present in animal milk and it is digested (broken in its units) by the lactase enzyme.

Some people are lactose intolerant because their bodies is not able to produce the enzyme. If they ingest dairy products it may cause health issues. Nowadays it is possible to purchase the lactase enzyme and ingest it with a dairy food to avoid any health effects.

3 0
3 years ago
A gas at 20.0°C is increased to 40.0°C, will its volume: if the original volume is 1.00 l, what would the new volume be
Leona [35]

Answer:

2.0 l

Explanation:

When for 20 °C volume is 1 l then for 40°C is going to be 2 l

20-------1

40-------x

x=(40*1):20

6 0
3 years ago
Question 1 of 6
Juli2301 [7.4K]

Answer:

Option A. 2, 3, 2

Explanation:

We'll begin by balancing the equation. This can be achieved by doing the following:

Fe + Cl2 —> FeCl3

There are 2 atoms of Cl on the left side and 3 atoms on the right side. It can be balance by putting 3 in front of Cl2 and 2 in front of FeCl3 as shown below:

Fe + 3Cl2 —> 2FeCl3

There are 2 atoms of Fe on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Fe as shown below:

2Fe + 3Cl2 —> 2FeCl3

Now the equation is balanced.

The coefficients are : 2, 3, 2

8 0
3 years ago
The final volume of the solution is 284 mL. What is the concentration of CuSO4 in the final solution, in mol/L?
DochEvi [55]

Answer:

0.0252mol/L

Explanation:

The following data were obtained obtained from the question:

Volume of solution = 284mL = 284/1000 = 0.284L

Mole of CuSO4 = 7.157 × 10^-3 mol

Molarity =?

Molarity = mole/Volume

Molarity = 7.157x10^-3 /0.284

Molarity = 0.0252mol/L

The concentration of the solution is 0.0252mol/L

7 0
3 years ago
1) A car is traveling down the interstate at 37.1 m/s. The driver sees a cop and quickly slows down. If the driver slows to 29.8
WITCHER [35]

1)

The acceleration of the car is the rate of change of velocity of the car; it can be calculated as:

a=\frac{v-u}{t}

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity of the car to change from u to v

In this problem, for this car we have:

u = 37.1 m/s

v = 29.8 m/s

t = 3 s

So, the acceleration is:

a=\frac{29.8-37.1}{3}=-2.43 m/s^2

2)

The work done in lifting the box is equal to the potential energy transferred to the box during the process; it is given by:

W=Fd

where

F is the force applied

d is the displacement of the box

Here we have:

F = 87.3 N is the force applied

d = 2.04 m is the displacement of the box

So, the work done to lift the box is:

W=(87.3)(2.04)=178.1 J

3)

The power is the rate of work done per unit time. It is calculated as:

P=\frac{W}{t}

where

W is the work done

t is the time taken to do the work

For the child in this problem, we have:

W = 1250 J is the work done by the child running up the stairs

P = 267 W is the power used

Therefore, re-arranging the equation, we find the time taken:

t=\frac{W}{P}=\frac{1250}{267}=4.68 s

4)

The kinetic energy of an object is the energy possessed by the object due to its motion. Mathematically, it is given by

KE=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the rabbit in this problem, we have:

m = 8.642 kg is the mass of the rabbit

KE = 125.6 is its kinetic energy

Solving the formula for v, we find the speed of the rabbit:

v=\sqrt{\frac{2KE}{m}}=\sqrt{\frac{2(125.6)}{8.642}}=5.4 m/s

5)

The efficiency of a machine is the ratio between the energy produced in output by the machine and the work done in input. Mathematically, it is given by

\eta = \frac{E_{out}}{W_{in}}\cdot 100

where

E_{out} is the energy in output

W_{in} is the work in input

For the machine in this problem,

W_{in}=120 J is the work in input

E_{out}=93 J is the energy in output

Therefore, the efficiency of this machine is:

\eta=\frac{93}{120}\cdot 100=77.5\%

6)

During a collision, the total momentum of the system is always conserved before and after the collision. So we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 =(m_1+m_2)v

where

m_1=212 kg is the mass of the first car

u_1=8.00 m/s is the initial velocity of the first car

m_2=196 kg is the mass of the 2nd car

u_2=6.75 m/s is the initial velocity of the 2nd car

v is the final velocity of the two cars stuck together (after the collision, they move together)

Solving the equation for v, we find:

v=\frac{m_1 u_1 +m_2 u_2}{m_1 +m_2}=\frac{(212)(8.00)+(196)(6.75)}{212+196}=7.40 m/s

7)

The relationship between speed, frequency and wavelength of a wave is given by the wave equation:

v=f\lambda

where

v is the speed of the wave

f is the frequency of the wave

\lambda is the wavelength

For the wave in the string in this problem we have:

\lambda=0.23 m (wavelength)

f = 12 Hz (frequency)

So, the speed of the wave is:

v=(12)(0.23)=2.76 m/s

8)

The relationship between frequency and wavelength for an electromagnetic wave is given by

c=f\lambda

where:

c is the speed of light in a vacuum

f is the frequency of the wave

\lambda is the wavelength of the wave

For the blue light in this problem, we have

f=6.2\cdot 10^{14}Hz (frequency)

while the speed of light is

c=3.0\cdot 10^8 m/s

So, the wavelength of blue light is:

\lambda=\frac{c}{f}=\frac{3.0\cdot 10^8}{6.2\cdot 10^{14}}=4.8\cdot 10^{-7} m

9)

The sound wave in this problem travels with uniform motion (=constant velocity), therefore we can use the following equation:

d=vt

where

d is the distance covered by the wave

v is the speed of the wave

t is the time elapsed

In this problem:

v = 343 m/s is the speed of the sound wave

t = 0.287 s is the time elapsed

So, the distance covered by the wave is

d=(343)(0.287)=98.4 m

3 0
3 years ago
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