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Arlecino [84]
3 years ago
12

Which of the following are weak electrolytes in aqueous solutions? Select ALL that apply.

Chemistry
1 answer:
Mandarinka [93]3 years ago
3 0

Answer:

Weak electrolytes are

HgCl2 and NH₃

Explanation:

  • Electrolytes are compounds that conduct electricity while in molten or aqueous form.
  • Electrolytes may therefore be decomposed by passing electric current through them.
  • They may be either strong or weak electrolytes.
  • Strong electrolytes are those that ionize completely to form mobile ions while weak electrolytes ionize partially to generate ions.
  • Examples of weak electrolytes  are HgCl2, NH₃
  • Examples of strong electrolytes are LiOH, HClO₄, and HI.

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An unknown element "x" can form a compound with the formula "x"br2. in which main group on the periodic table would element "x"
Hoochie [10]
Group 2, or in the Alkaline Earth Metals section. This is due to the necessity to have a +2 charge to balance out or negate the -2 charge two Bromines carry.
4 0
3 years ago
Calculate the volume of each of the following gases at STP
kherson [118]
For Ar :

1 mol ------------ 22.4 L ( at STP )
7.6 mol ---------- x L 

x = 7.6 * 22.4

x = 170.24 L
-----------------------------------------------------------------
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hope this helps !.



7 0
3 years ago
What is the easiest way for atoms without a full valence shell to gain a full valence shell?
sergey [27]

Most atoms do not. For those atoms that do not have a full valence shell (which usually would contain eight electrons, except for hydrogen and helium, where it would contain two), something has to change. So nature's tendency toward a full valence shell will lead to one of two things: The gain or loss of electrons.

7 0
3 years ago
Read 2 more answers
What is the molarity of the potassium hydroxide if 25.25 mL of KOH is required to neutralize 0.500 g of oxalic acid, H2C2O4? H2C
Greeley [361]

Answer:

0.444 mol/L

Explanation:

First step is to find the number of moles of oxalic acid.

n(oxalic acid) = \frac{0.5g}{90.03 g/mol} = 5.5537*10^{-3} mol\\

Now use the molar ratio to find how many moles of NaOH would be required to neutralize 5.5537*10^{-3} mol\\ of oxalic acid.

n(oxalic acid): n(potassium hydroxide)

         1           :            2                  (we get this from the balanced equation)

5.5537*10^{-3} mol\\ : x

x = 0.0111 mol

Now to calculate what concentration of KOH that would be in 25 mL of water:

c = \frac{number of moles}{volume} = \frac{0.0111}{0.025} = 0.444 mol/L

5 0
3 years ago
SOMEONE EXPLAIN THIS TO ME?!?!
labwork [276]

Answer:

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Explanation:

Due to the tartaric acid present in these substances, this is a weak acid and is the predominant type of acid in grapes.

pH meters for these substances, measure the total acidity of the sample and convert it into tartaric acid concentration; The test strips are a qualitative method of measurement and their result can give different opinions.

7 0
3 years ago
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