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Roman55 [17]
3 years ago
5

If 625 ml of pure water is added to 344 ml of 1.675 m na2so4, what is the new concentration of na2so4?

Chemistry
1 answer:
Marianna [84]3 years ago
8 0
Molar concentration is the number of Na₂SO₄ moles that are dissolved in 1 L of solution.
when 625 mL is added to 344 mL of Na₂SO₄, then the number of moles that are dissolved in 344 mL remains constant but volume increases. Therefore concentration now decreases. 
Molar concentration of Na₂SO₄ is 1.675 M
the number of Na₂SO₄ moles  in 1000 mL - 1.675 mol
then number of Na₂SO₄ moles in 344 mL - 1.675 mol / 1000 x 344 = 0.5762 mol
the new volume - 344 mL + 625 mL = 969 mL
concentration = number of moles / volume
therefore new concentration = 0.5762 mol / 0.969 L = 0.595 mol/L
new concentration of Na₂SO₄ is 0.595 M
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atoms with same number of valence electrons are grouped in to columns called groups.

therefore elements of the same group have same number of valence electrons, hence similar chemical properties.

from the options given

only Be and Mg belong to the same group they both belong to group 2 with 2 valence electrons

therefore Be and Mg have similar chemical properties

answer is

1) Be and Mg

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3 years ago
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What is the total number of moles of atoms in one mole of (NH4)2SO4? 1. 10 2. 11 3. 14 4. 15
Neporo4naja [7]

Answer:

4. 15

Explanation:

The given formula is:- (NH_4)_2SO_4

1 mole of the salt contains 2 moles of nitrogen atom, 8 moles of hydrogen, 1 mole of sulfur and 4 moles of oxygen atom as can be seen from the formula.

Thus,

1 mole of salt contains total of 15 moles of the atoms which constitute the salt.

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A chemist requires 0.802 mol Na2CO3 for a reaction. How many grams does this correspond to?
Komok [63]

Answer:

Ok:

Explanation:

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7 0
2 years ago
When 1 mole of H2(g) reacts with F2(g) to form HF(g) according to the following equation, 542 kJ of energy are evolved H2(g) + F
topjm [15]

Answer: The reaction is exothermic. The value of q is  -542 kJ.

Explanation:

Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and  for the reaction comes out to be positive.

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and  for the reaction comes out to be negative.

Thus H_2(g)+F_2(g)\rightarrow 2HF(g) evolves heat , it is exothermic in nature. The value of q is -542kJ.

7 0
3 years ago
Determine the molality of a solution of methanol dissolved in ethanol for which the mole fraction of methanol is 0.135. Give you
Alja [10]

<u>Answer:</u> The molality of the solution is 0.11 m

<u>Explanation:</u>

We are given:

Mole fraction of methanol = 0.135

This means that 0.135 moles of methanol is present in 1 mole of a solution

Moles of ethanol = 1 - 0.135 = 0.865 moles

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of ethanol = 0.865 moles

Molar mass of ethanol = 46 g/mol

0.865mol=\frac{\text{Mass of ethanol}}{46g/mol}\\\\\text{Mass of ethanol}=(0.865mol\times 46g/mol}=39.79g

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (methanol) = 0.135 g

M_{solute} = Molar mass of solute (methanol) = 32 g/mol

W_{solvent} = Mass of solvent (ethanol) = 39.79 g

Putting values in above equation, we get:

\text{Molality of methanol}=\frac{0.135\times 1000}{32\times 39.79}\\\\\text{Molality of methanol}=0.106m\approx 0.11m

Hence, the molality of the solution is 0.11 m

6 0
3 years ago
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