a) The motion along the vertical direction and the motion along the horizontal direction.
b) The object remains in the air for a time period of 2usin(θ)/g.
Any object that is thrown in the air when gravity is acting on it is called a projectile. The motion of this projectile is called projectile motion.
When the projectile is thrown in the air at some angle θ, then there are two independent motions taking place at the same time. First is the component of motion along the vertical direction along which gravity acts. Second is the component of motion along the horizontal direction along which the object moves with a constant velocity. No force acts along the horizontal direction. The horizontal motion does not affect the vertical motion and the converse is also true. So these are independent of each other.
The time of flight is the time during which a projectile remains in the air. This time of flight is calculated using the formula,
T=2usin(θ)/g
where T is the time of flight, u is the initial velocity and g is the acceleration due to gravity.
Hence, the object remains in the air for a time period of 2usin(θ)/g.
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Answer:
0.000000113 or 1.13* meters
Explanation:
One nanometer is meters. So 113 nanometers would be 113*, or 1.13* meters. That's expessed on "cientific notation." On the "usual" notation, it will be 0.000000113 meters.
Answer:
67.6 m
Explanation:
For this problem, we just need to analyze the motion of the two planes after the collision.
The two planes stick together and move with a velocity of
u = 19.3 m/s
The problem tells us that they skid until they stop: so, their final velocity is
v = 0
Since the velocity is not constant, this means that they are accelerating.
We also know that they skid for a time of
t = 7 s
Therefore, we can find their stopping distance using the following suvat equation
And substituting, we find
Answer:
It keeps our body hydrated.
Explanation:
Answer:
Given:
Initial velocity (u) = 0 m/s
Final velocity (v) = 44 m/s
Acceleration (a) = 5 m/s²
To Find:
Time taken (t)
Explanation:
From equation of motion we have:
By substituting value of u, v & a in the equation we get: