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Dimas [21]
3 years ago
12

Humberto builds two circuits using identical components.

Physics
2 answers:
vlada-n [284]3 years ago
6 0

Humberto should expect to see that all bulbs in circuit 1 will shine more dimly than the original bulbs, while all bulbs in circuit 2 will have the same brightness as the original bulbs.

B) All bulbs in circuit 1 will shine more dimly than the original bulbs, while all bulbs in circuit 2 will have the same brightness as the original bulbs.

Bumek [7]3 years ago
5 0

Answer:

B) All bulbs in circuit 1 will shine more dimly than the original bulbs, while all bulbs in circuit 2 will have the same brightness as the original bulbs.

Explanation:

When we connect more bulbs in circuit 1 where all are connected in series then the net resistance of the circuit will increase and voltage across each bulb will decrease.

So as per the formula

P = \frac{V^2}{R}

so here since voltage decreases across each bulb so we can say that power across each bulb will decrease and bulb gets more dimmy then initially connected bulbs

When we connect bulbs in parallel then voltage across each bulb will remain same and then the brightness of each bulb will remain constant.

So correct answer will be

B) All bulbs in circuit 1 will shine more dimly than the original bulbs, while all bulbs in circuit 2 will have the same brightness as the original bulbs.

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An AC generator consists of 20 circular loops of wire with an area of 75 cm2. It has a maximum induced voltage of 24 V. If its a
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Faraday's law allows us to find the magnetic field that produces the emf in the rotating system is:

  • The magnetic field is:  B = 0.424 T

Faraday's law of induction states that when the magnetic flux changes in time, an induced electromotive force is produced.

            fem = - \frac{d \Phi_B }{dt}  

where fem is the induced electromotive force and Ф the flux,

The magnetic flux is the scalar product of the field and the area.

           \Phi_B = B . A = B A  \ cos \theta  

In this case we have several turns, so the expression remains.

           fem = - N B A \ \frac{d cos \theta}{dt}  

Indicate that the turns rotate at a constant frequency, therefore we can use the uniform rotational motion ratio.

           

           θ = w t

We substitute

 

         fem = - N B A \ \frac{d \ cos \ wt}{dt}\\fem =  N B A w sin \ wt

the maximum induced electromotive force occurs when the sine function is ±1

          fem = N B A w

They indicate that the fem = 24 V, the number of the turn is N = 20, the area is A = 75 cm² = 75 10⁻⁴ m² and the frequency f = 60 Hz

Frequency and angular velocity are related.

           w = 2π f

We substitute.

           fem = N B A 2π f

           B = \frac{fem }{2 \pi \ NA \ f}  

Let's calculate.

         B= \frac{24 }{2\pi \ 20 \ 75 \ 10^{-4} 60}B = 24 / 2pi 20 75 10-4 60

         B = 0.424 T

In conclusion, using Faraday's law we can find the magnetic field that produces the emf in the rotating system is:

  • The magnetic field is; B = 0.424 T

Learn more about Faraday's law here:  brainly.com/question/24617581

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