1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ioda
3 years ago
14

9. How much work is done when a 15kg box is lifted to a height of 2 meters?

Physics
1 answer:
torisob [31]3 years ago
5 0

Answer: W = 294 J

Explanation: Solution:

Work is expressed as the product of force and the distance of the object.

W = Fd        where F = mg

W= Fd

   = mg d

   = 15 kg ( 9.8 m/s²) ( 2m )

   = 294 J

You might be interested in
A 3.53-g lead bullet traveling at 428 m/s strikes a target, converting its kinetic energy into thermal energy. Its initial tempe
Taya2010 [7]

Complete question:

A 3.53-g lead bullet traveling at 428 m/s strikes a target, converting its kinetic energy into thermal energy. Its initial temperature is 40.0°C. The specific heat is 128 J/(kg · °C), latent heat of fusion is 24.5 kJ/kg, and the melting point of lead is 327°C.

(a) Find the available kinetic energy of the bullet. J

(b) Find the heat required to melt the bullet. J

Answer:

Part (a) the available kinetic energy of the bullet is 323.32 J

Part (b) the heat required to melt the bullet is 216.17 J

Explanation:

Given;

mass of the bullet = 3.53 g = 0.00353 kg

velocity of the bullet = 428 m/s

initial temperature of the bullet = 40.0°C

final temperature of the bullet =  327°C

specific heat capacity, c= 128 J/(kg · °C)

latent heat of fusion, Hf  = 24.5 kJ/kg

Part (a) the available kinetic energy of the bullet. J

KE = ¹/₂ × mv²

KE = ¹/₂ × 0.00353 × 428²

     = 323.32 J

Part (b) the heat required to melt the bullet. J

This is the thermal energy required to increase the temperature of the bullet and the heat energy required to melt the bullet.

Quantity of heat required to raise the temperature of the bullet:

Q = mcΔT

   = 0.00353 × 128 × (327-40)

   = 0.00353 × 128 × 287

   = 129.68 J

Quantity of heat required to melt the bullet:

Q = mH_f

Q = 0.00353 × 24500

   = 86.49 J

TOTAL energy required to melt the bullet = 129.68 J + 86.49 J

                                                                      = 216.17 J

3 0
3 years ago
An object moving in a constant velocity will always have a
jeka94

Answer:

constant velocity unless acted on my an opposite force

7 0
3 years ago
Bicycle in its writers have combined a mass of 80 kg in a speed of 6.0 meters per Second what is the magnitude of the average fo
erik [133]

Answer:

F = 120 N

Explanation:

Force x distance = energy

The bike has energy 1/2 . 80 . 6^2   = 1440 J

You are looking at an example of not reading the question properly.

Impulse = Force . time  = change in momentum

F . 4  = 80 .6

F = 120 N

7 0
3 years ago
Two plane mirrors are separated by 120°, as the drawing illustrates. If a ray strikes mirror M1 at a θ1 = 64° angle of incidence
tino4ka555 [31]

Angle, θ2 at which the light leaves mirror 2 is 56°

<u>Explanation:</u>

Given-

θ1 = 64°

So, α will also be 64°

According to the figure:

α + β = 90°

So,

β = 90° - α

  = 90° - 64°

  = 26°

β + γ + 120° = 180°

γ = 180° - 120° - β

γ = 180° - 120° - 26°

γ = 34°

γ + δ = 90°

δ = 90° - γ

δ = 90° - 34°

δ = 56°

According to the law of reflection,

angle of incidence = angle of reflection

θ2 = δ = 56°

Therefore, angle θ2 at which the light leaves mirror 2 is 56°

8 0
3 years ago
Describes the relationship between the free energy change, the reaction quotient, and the equilibrium constant.
LUCKY_DIMON [66]

<u>Explanation:</u>

Reaction quotient is defined as the ratio of the concentration of the products and reactants of a reaction at any point of time with respect to some unit. It is represented by the symbol <em>Q</em>.

The ratio of the concentration of products and reactants of a reaction in equilibrium with respect to some unit is said to be equilibrium constant expression. It is represented by the symbol <em>K</em>.

The relationship between Gibbs free energy change and reaction quotient of the reaction is:

\Delta G=\Delta G^o+RT ln Q           ......(1)

where,

\Delta G = Gibbs free energy change

\Delta G^o = Standard Gibbs free energy change

R = Gas constant

T = Temperature

At equilibrium, the free energy change of the reaction becomes 0 and standard Gibbs free energy change can be related to the equilibrium constant by the equation:

\Delta G^o=-RT ln Q           ...(2)

4 0
3 years ago
Other questions:
  • The internal energy of a material is determined by
    14·2 answers
  • A spaceship moving through deep space will continue moving at the same speed forever. What is the name of the property that allo
    11·2 answers
  • The current in a hair dryer measures 20.0 amps. The resistance of the hair dryer is 6 ohms. What is the voltage?
    14·1 answer
  • _____ is the rate of change in velocity.
    9·2 answers
  • A total charge of –6.50 µC is uniformly distributed within a sphere that has a radius of 0.150 m. What is the magnitude and dire
    15·1 answer
  • The unit of force, Newton is a derived unit. (give reasons) ​
    8·1 answer
  • There is a limit to how long your neck can be. If your neck were too long, no blood would reach your brain! What is the maximum
    14·1 answer
  • Which galaxy is the most stretched out?<br>​
    9·2 answers
  • Find the number of moles and the number of molecules in one cubic meter of air at 1 atmospheric pressure and 0C.
    11·1 answer
  • Habiba and selehadin have measured the voltage across a resistor to be 5.26V and the current flowing through in to be 0.41A they
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!