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1 year ago

A stone is thrown at 45 degree with velocity 10m/sec.calculate the range of projectile

Physics

1 answer:

BARSIC [14]1 year ago

8 0

Answer:

As per Given Information

Angle on which the stone thrown ,theta = 45°

Velocity ,u = 10m/s

Acceleration due to gravity ,g is 10m/s²

We have to find the "Range of Projectile "

Range of projectile is denoted by R .

Using Formulae

$\\ \bigstar{\boxed{\pink{\bf{R = \frac{ {u}^{2}sin2 \theta }{g} }}}} \\ \\$

On putting the value we get

$\sf\dashrightarrow \: R\: = \frac{ {10}^{2} \times sin(2 \times 45) }{10} \\ \\ \sf\dashrightarrow \: R = \frac{100 \times sin90 {}^{ \circ} } {10} \\ \\ \sf\dashrightarrow \: R \: = \frac{100 \times 1}{10} \\ \\ \sf\dashrightarrow \: R \: = \frac{100}{10} \\ \\ \sf\dashrightarrow \: R = \cancel \frac{100}{10} \\ \\ \sf\dashrightarrow \: R = 10m$

So, the range of projectile is 10m.

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3 years ago

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Learn more about circular motion:

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3 years ago

A stone is thrown at 45 degree with velocity 10m/sec.calculate the range of projectile​

A stone is thrown at 45 degree with velocity 10m/sec.calculate the range of projectile