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masya89 [10]
2 years ago
13

A stone is thrown at 45 degree with velocity 10m/sec.calculate the range of projectile​

Physics
1 answer:
BARSIC [14]2 years ago
8 0

Answer:

As per Given Information

Angle on which the stone thrown ,theta = 45°

Velocity ,u = 10m/s

Acceleration due to gravity ,g is 10m/s²

We have to find the "Range of Projectile "

Range of projectile is denoted by R .

Using Formulae

\\  \bigstar{\boxed{\pink{\bf{R =    \frac{ {u}^{2}sin2 \theta }{g}  }}}} \\  \\

On putting the value we get

\sf\dashrightarrow \: R\:  =  \frac{ {10}^{2} \times sin(2 \times 45) }{10}  \\  \\  \sf\dashrightarrow \: R =   \frac{100 \times sin90 {}^{ \circ} }  {10}  \\  \\  \sf\dashrightarrow \: R \:  =  \frac{100 \times 1}{10}   \\  \\  \sf\dashrightarrow \: R \: =  \frac{100}{10}  \\  \\  \sf\dashrightarrow \: R  =  \cancel \frac{100}{10}  \\  \\  \sf\dashrightarrow \: R  = 10m

So, the range of projectile is 10m.

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15. Find the speed of a disc of radius 0.5 meters and mass 2-kg at the base of the incline. The disc starts at rest and rolls do
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3 years ago
What does this tell you about the direction and magnitude of the acceleration acting on the cannonball throughout its duration o
Lyrx [107]

Answer:

Direction remains the same but velocity changes.

Explanation:

This tell us about the direction and magnitude of the acceleration acting on the cannonball throughout its duration of flight that its direction remains the same but its magnitude of the acceleration is continuously changing. The cannonball moves in the direction in which the cannon was fired while the velocity is highest after the fire but decreases when goes higher and when it comes back to the ground so its velocity increases against so we can say that both positive and negative acceleration occurs. Positive acceleration means increase in the magnitude of velocity whereas negative acceleration means decrease in velocity.

3 0
3 years ago
Two steel guitar strings have the same length. String A has a diameter of 0.513 mm and is under 403 N of tension. String B has a
Mnenie [13.5K]

Answer:

\frac{v_{A}}{v_{B}} = 1.785

Explanation:

T_{A} = Tension force in string A = 403 N

T_{B} = Tension force in string B = 800 N

d_{A} = diameter of string A = 0.513 mm

d_{B} = diameter of string B = 1.29 mm

v_{A} = wave speed of string A

v_{B} = wave speed of string B

Ratio of the wave speeds is given as

\frac{v_{A}}{v_{B}} = \sqrt{\frac{T_{A}}{T_{B}}} \left ( \frac{d_{B}}{d_{A}} \right )

\frac{v_{A}}{v_{B}} = \sqrt{\frac{403}{800}} \left ( \frac{1.29}{0.513} \right )

\frac{v_{A}}{v_{B}} = 1.785

5 0
3 years ago
You are rushing to the train station to catch your morning commute. The train leaves the train station from rest with an acceler
Vanyuwa [196]

Answer:

a) t= 4.81 s,and t= 23.51.

b)d=6.88 m

c)v=4.8 m/s

Explanation:

Acceleration of train ,a= 0.6 m/s²

u = 0 m/s

Your speed ,V= 8.5 m/s

Lets take after t time he you catch the train

Distance travel by train in t time

d=ut+\dfrac{1}{2}at^2

d=\dfrac{1}{2}\times 0.6\times t^2  ----------1

d= V ( t- 4)

d= 8.5 ( t- 4)  --------2

By equating equation 1 and 2

0.3 t² =  8.5 ( t- 4)

0.3 t² -8.5 t + 34 = 0

t= 4.81 s and t= 23.51

It means that you will catch train after t= 4.81 s,and t= 23.51.

t=23.51 sec means that you will catch the train after 23.51 sec also because acceleration of train is low.

Distance travel

d= 8.5 ( t- 4)

t= 4.81 s

d= 8.5 ( 4.81- 4)  m

d=6.88 m

Lets speed = v

0.3 t² =  v ( t- 4)

0.3 t² - v t + 4 v = 0

To have one solution

D=\sqrt{b^2-4ac}

D= 0 Should be zero.

v²- 4 x 0.3 x 4 v

v = 4 x 0.3 x 4

v=4.8 m/s

6 0
3 years ago
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