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masya89 [10]
2 years ago
13

A stone is thrown at 45 degree with velocity 10m/sec.calculate the range of projectile​

Physics
1 answer:
BARSIC [14]2 years ago
8 0

Answer:

As per Given Information

Angle on which the stone thrown ,theta = 45°

Velocity ,u = 10m/s

Acceleration due to gravity ,g is 10m/s²

We have to find the "Range of Projectile "

Range of projectile is denoted by R .

Using Formulae

\\  \bigstar{\boxed{\pink{\bf{R =    \frac{ {u}^{2}sin2 \theta }{g}  }}}} \\  \\

On putting the value we get

\sf\dashrightarrow \: R\:  =  \frac{ {10}^{2} \times sin(2 \times 45) }{10}  \\  \\  \sf\dashrightarrow \: R =   \frac{100 \times sin90 {}^{ \circ} }  {10}  \\  \\  \sf\dashrightarrow \: R \:  =  \frac{100 \times 1}{10}   \\  \\  \sf\dashrightarrow \: R \: =  \frac{100}{10}  \\  \\  \sf\dashrightarrow \: R  =  \cancel \frac{100}{10}  \\  \\  \sf\dashrightarrow \: R  = 10m

So, the range of projectile is 10m.

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