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3 years ago

What does a tree do to maintain homeostasis during the winter months?

Physics

1 answer:

grin007 [14]3 years ago

6 0

Answer:

During dormancy, a tree's metabolism, energy consumption, and growth all slow down significantly in order to endure the harsh season of winter when water and sunlight are more scarce.

Explanation:

hope it helps

mark me brainliest pls

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1) Use SolidWorks (SW) FEA to apply a bending load of 600 lbf on the right end of the stepped shaft as shown below. This is the

salantis [7]

Solution :

Given :

L = 1 in

d = 0.75 in

D = 1 in

Fillet radius, r = 0.063 in

$K_{t_{bending}=\frac{\sigma_{FEA_{bending }}}{\sigma_{Nominal_{bending }}}$

We know that :

$\sigma_{b} = \frac{32M}{\pi d^3}$

$\sigma_{b} = \frac{32 \times (2998.63 \times 25.4)}{\pi (0.75 \times 25.4)^3}$

$=112.27 \ N/mm^2$

$\sigma_{FEA} = 1.3 \times 10^8 \ N/m^2$

$=1.3 \times 10^8 \times 10^{-6}$

$=1.3 \times 10^2$ MPa

= 130 MPa

Therefore, the stress concentration factor is :

$k_t=\frac{130}{112.27}$

= 1.157922

8 0

3 years ago

What is the speed in km/min of a skater who travels a distance of 210 m in a time of 30 seconds

Artyom0805 [142]

Answer: 0.42 km/min

Explanation:

total distance traveled(in meters) = 210m

total distance traveled(in km) = 210 ÷ 1000 = 0.21 km

total time taken(in seconds) = 30 s

total time taken(in minutes) = 30 ÷ 60 = 0.5 s

speed =(distance traveled)÷(time taken)[in km/min] = 0.21 ÷ 0.5 = 0.42km/min

7 0

3 years ago

1. Calculate the velocity of a 0.8 kg kitten with a forward momentum of 5 kg*m/s.

V125BC [204]

Q.1

Answer . Momentum = mass x velocity

Momentum/mass = velocity

5/0.8 = velocity

6.25 m/s = velocity

Q.2

Answer . F = ma => a = f/m => a = 7/3.2 => a = 2.1875m/s²

3 0

4 years ago

Calculate the displacement of a bee that flew out of the beehive due east for 4 km, went around a 0.52 m in diameter poplar tree

stiks02 [169]

Answer:

the only thing thats confusing me is no ?

Explanation:

please explain thank you :)

3 0

3 years ago

The filament of a certain lamp has a resistance that increases linearly with temperature. When a constant voltage is switched on

sashaice [31]

To solve this problem we can apply the concept related to thermal expansion, including the analogy with resistance and final intensity.

The mathematical expression that describes the expansion of a material by a thermal process is given by

$R = R_0\alpha \Delta T$

Where

$R_0$ = Initial resistance

$\alpha =$ Thermal expansion coefficient

$\Delta T =$ Change in the temperature

If we want to directly obtain the final value of the resistance of the object, you would simply add the initial resistance to this equation - because at this moment we have the result of how much resistance changed, but not of its final resistance - So,

$R_f = R_0 + L_0\alpha \Delta T$

$R_f = R_0(1 + \alpha \Delta T)$

Re-arrange to find the change at the temperature,

$\Delta T=\frac{1}{\alpha}\frac{R_f}{R_0}-1}$

Since the resistance is inversely proportional to the current and considering that the voltage is constant then

$R \propto \frac{1}{I}$

Then,

$\Delta T=\frac{1}{\alpha}\frac{I_0}{I_f}-1}$

$\Delta T = \frac{1}{4.5*10^{-3}}(\frac{I_0}{I_0/8}-1)$

$\Delta T = \frac{1}{4.5*10^{-3}}(8-1)$

$\Delta T = 1555.5k$

<em>(It is possible that there is a typing error and the value is not 4.5 but 4.3, so the closest approximate result would be 1627K and mark this as the correct answer)</em>

6 0

3 years ago