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3 years ago

What does a tree do to maintain homeostasis during the winter months?

Physics

1 answer:

grin007 [14]3 years ago

6 0

Answer:

During dormancy, a tree's metabolism, energy consumption, and growth all slow down significantly in order to endure the harsh season of winter when water and sunlight are more scarce.

Explanation:

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You might be interested in

Bowen’s reaction series illustrates relations between:

Finger [1]

C. Temperature, chemical composition and mineral structure

Explanation:

The Bowen's reaction series illustrates the relationship between temperature, chemical composition and mineral structure.

The series is made up of a continuous and discontinuous end through which magmatic composition can be understood as temperature changes.

The left part is the discontinuous end while the right side is the continuous series.
From the series, we understand that a magmatic body becomes felsic as it begins to cool to lower temperature.
A magma at high temperature is ultramafic and very rich in ferro-magnesian silicates which are the chief mineral composition of olivine and pyroxene. These minerals are predominantly found in mafic- ultramafic rocks. Also, we expect to find the calcic-plagioclase at high temperatures partitioned in the magma.
At a relatively low temperature, minerals with frame work structures begins to form . The magma is more enriched with felsic minerals and late stage crystallization occurs here.

Learn more:

Silicate minerals brainly.com/question/4772323

#learnwithBrainly

5 0

4 years ago

What is the Galaxy we live in called?

Fittoniya [83]

The Milky Way is a spiral galaxy type so it has arms sort of like an octopus. We live in the Milky Way

7 0

3 years ago

Read 2 more answers

A person in the back of a pick-up moving at 20 m/s relative to the Earth, throws a baseball with a speed of 15 m/s in a directio

Bumek [7]

Answer:

This is known as a Galilean transformation where

V' = V - U

Where the primed frame is the Earth frame and the unprimed frame is the frame moving with respect to the moving frame

V - speed of object in the unprimed frame

U - speed of primed frame with respect to the unprimed frame

Here we have:

V = -15 m/s speed of ball in the moving frame (the truck)

U = -20 m/s speed of primed (rest) frame with respect to moving frame

So V' = -15 - (-20) = 5 m/s

It may help if you draw a vector representing the moving frame and then add

a vector representing the speed of the ball in the moving frame.

3 0

3 years ago

A car which is traveling at a velocity of 15 m/s undergoes an acceleration of 6.5 m/s2 over a distance of 340 m. How fast is it

fomenos

Answer:68.15m/s

Explanation:

<u><em>Given: </em></u>

v₁=15m/s

a=6.5m/s²

v₁=?

x=340m

<u><em>Formula:</em></u>

v₁²=v₁²+2a (x)

<u>Set up:</u>

= $\sqrt{15m/s} ^{2} +2(6.5m/s^2)(340m)$

<h2><u><em>Solution:</em></u></h2><h2><u><em>68.15m/s</em></u></h2>

<u />

6 0

3 years ago

A mass weighing 14 pounds stretches a spring 2 feet. The mass is attached to a dashpot device that offers a damping force numeri

Elodia [21]

Answer:

The motion is over-damped when λ^2 - w^2 > 0 or when $b^{2}$ > 0.86

The motion is critically when λ^2 - w^2 = 0 or when $b^{2}$ = 0.86

The motion is under-damped when λ^2 - w^2 < 0 or when $b^{2}$ < 0.86

Explanation:

Using the newton second law

k is the spring constante

b positive damping constant

m mass attached

$m\frac{d^{2} x}{dt^{2}} = - kx - b\frac{dx}{dt}$

x(t) is the displacement from the equilibrium position

$\frac{d^{2} x}{dt^{2}} +\frac{b}{m}\frac{dx}{dt} + \frac{k}{m}x = 0$

Converting units of weights in units of mass (equation of motion)

$m = \frac{W}{g} = \frac{14}{32} = 0.43 slug$

From hook's law we can calculate the spring constant k

$k = \frac{W}{s} = \frac{14}{2} = 7 lb/ft$

If we put m and k into the DE, we get

$\frac{d^{2} x}{dt^{2}} +\frac{b}{0.43}\frac{dx}{dt} + 16.28x = 0$

Denoting the constants

2λ = $\frac{b}{m}$ = $\frac{b}{0.43}$

λ = b/0.215

$w^{2} = \frac{k}{m} = 16.28$

λ^2 - w^2 = $\frac{b^{2} }{0.046} - 16.28$

This way,

The motion is over-damped when λ^2 - w^2 > 0 or when $b^{2}$ > 0.86

The motion is critically when λ^2 - w^2 = 0 or when $b^{2}$ = 0.86

The motion is under-damped when λ^2 - w^2 < 0 or when $b^{2}$ < 0.86

3 0

4 years ago