F(x)=2(3)-5
f(x)=6-5
f(x)=1
Answer:13y(x-4)
Step-by-step explanation:
13xy-52y =13y(x-4)
Answer:
is the correct answer.
Step-by-step explanation:
We know that vertex equation of a parabola is given as:

where
is the vertex of the parabola and
are the coordinate of points on parabola.
As per the question statement:
The parabola opens upwards that means coefficient of
is positive.
Let 
Minimum of parabola is at x = 3.
The vertex is at the minimum point of a parabola that opens upwards.

Putting value of a and h in the equation:

Formula used: 
Comparing the equation formulated above with the options given we can observe that the equation formulated above is most similar to option A.
Comparing
and
13 = 9+k
k = 4
Please refer to the graph attached.
Hence, correct option is 
Answer:
q= -ck+dp/
-k+d
Step-by-step explanation:
Step 1:
Multiply both sides by p.
dp=ck−kq+pq
Step 2:
Flip the equation.
ck−kq+pq=dp
Step 3:
Add -ck to both sides.
−kq+pq=−ck+dp
Step 4:
Factor out variable q.
q(−k+p)=−ck+dp
Step 5:
Divide both sides by -k+p.
q= -ck+dp/
-k+d
Sorry if it's all letters and u needed numbers.
-6x-x^2-8 = -(x+2) x (x+4)
(This is if you are factoring the expression)