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irga5000 [103]
3 years ago
7

A 6?-ft vertical post casts a 10?-in shadow at the same time a nearby cell phone tower casts a 120?-ft shadow. How tall is the c

ell phone? tower?
Mathematics
1 answer:
Advocard [28]3 years ago
3 0

Answer:

72?-ft

Step-by-step explanation:

The tower shadow is 12 times as long as that of the post, so the tower will be 12 times as high as the post.

... 12 × 6?-ft = 72?-ft

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The population of a city has decreased by 27% since it was last measured. If the current population is 7300, what was the previo
Tema [17]

Answer:

the answer is 9271

Step-by-step explanation:

if 7300 is 73%, then you need to add 27% to get 100% which is 9271

7 0
2 years ago
ASAP I NEED HELP <br> four 28s in lowest terms​
Margaret [11]

1/7 is the answer. 4/28 = 1/7 but in the lowest term

5 0
3 years ago
A sample of 11001100 computer chips revealed that 62b% of the chips fail in the first 10001000 hours of their use. The company's
STALIN [3.7K]

Answer:

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

z score = 1.35

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

Question; A sample of 1100 computer chips revealed that 62% of the chips fail in the first 1000 hours of their use. The company's promotional literature states that 60% of the chips fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that fail is different from the stated percentage. Determine the decision rule for rejecting the null hypothesis, H0, at the 0.10 level.

Step-by-step explanation:

Given;

n=1100 represent the random sample taken

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 1100

po = Null hypothesized value = 0.60

p^ = Observed proportion = 0.62

Substituting the values we have

z = (0.62-0.60)/√{0.60(1-0.60)/1100}

z = 1.354

z = 1.35

To determine the p value (test statistic) at 0.01 significance level, using a two tailed hypothesis.

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

3 0
3 years ago
PLEASE HURRY
horsena [70]

Answer:6,2

Step-by-step explanation:you need to add each step and divide

8 0
3 years ago
Read 2 more answers
Lynette buys candy at the grocery store. she gives half of the pieces to her son and 2 pieces to her daughter. if she has 4 piec
nevsk [136]

Let Lynette has originally candies in hand = x

She gave half to her son means x/2 given to son.

2 candies gave to daughter and left with 4.

x - x/2 - 2 = 4

adding 2 both sides

x - x/2 - 2 + 2 = 4 + 2

x - x/2 = 6

x /2 = 6

x = 12

Means she have 12 candies originally : Answer

Hope it will help :)

5 0
3 years ago
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