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3 years ago

7

A 6?-ft vertical post casts a 10?-in shadow at the same time a nearby cell phone tower casts a 120?-ft shadow. How tall is the c

ell phone? tower?

1 answer:

Advocard [28]3 years ago

3 0

Answer:

72?-ft

Step-by-step explanation:

The tower shadow is 12 times as long as that of the post, so the tower will be 12 times as high as the post.

... 12 × 6?-ft = 72?-ft

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BabaBlast [244]

$\underline{\bf{Given \:equation:-}}$

$\\ \sf{:}\dashrightarrow ax^2+by+c=0$

$\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.$

$\sf We\:know,$

$\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}$

$\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}$

$\underline{\large{\bf Identities\:used:-}}$

$\boxed{\sf (a+b)^2=a^2+2ab+b^2}$

$\boxed{\sf (√a)^2=a}$

$\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}$

$\boxed{\sf \sqrt{\sqrt{a}}=a}$

$\underline{\bf Final\: Solution:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}$

$\bull\sf Apply\: Squares$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}$

$\bull\sf Put\:values$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}$

$\bull\sf Simplify$

$\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}$

$\underline{\bf More\: simplification:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}$

$\underline{\Large{\bf Simplified\: Answer:-}}$

$\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}$

5 0

2 years ago

Read 2 more answers

Factor the polynomial 16b^4+30b^3-12b^2

Lelu [443]

Answer:

2b²(8b²+15b-6)

Step-by-step explanation:

16 $b^{4}$ +30b³-12b²

2b²(8b²+15b-6)

This is not further factorable. If you want to find the roots, you'd have to use the quadratic formula for the polynomial in the parentheses. Therefore that is our final answer.

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3 years ago

Need help with 13 asap

Whitepunk [10]

I’m hoping you are talking about:
Factor -1/2 out of -1/2x + 6
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-1/2(x-3)

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3 years ago

Evaluate 9(4x – 15) if x = 3.

4vir4ik [10]

Answer:

-27

Step-by-step explanation:

9(4x – 15)

Substitute 3 for x

9((4)(3) - 15)

Multiply (4)(3) = 12

9 ( 12 - 15 )

Subtract 12 - 15 = -3

9(-3)

Multiply 9(-3) = -27

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katen-ka-za [31]

Answer:

Step-by-step explanation:

The probability of drawing a red card is 1/2, since half of the cards in a deck are red. The probability of drawing an ace from a deck is 1/13, since there is an equal chance to pick any of the 13 numbers.

P(red card and ace)= P(red card)*P(ace)=1/2 * 1/13=1/26

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3 years ago