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3 years ago

-23 + 611 is closer to 0 than to 1. True or False

Mathematics

2 answers:

Schach [20]3 years ago

6 0

Answer: False

Step-by-step explanation:

kari74 [83]3 years ago

3 0

FASLE!!! because -23+611=588

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I need the statement and reasons <br>and whether its a sss sas asa hl

andrew-mc [135]

Answer:

it's sas

Step-by-step explanation:

statement: angle pqr is congruent to angle sqt. reason: they are vertical angles

statement: line pq is congruent to line qt

reason: definition of midpoint

statement: line sq is congruent to line qr

reason: definition of midpoint

hope this helps

3 0

2 years ago

What is the length of side x? If necessary, round your answer to two decimal places. 19 12

Valentin [98]

Answer:

D. 14.73

Step-by-step explanation:

According to Pythagoras,

19^2 = 12^2 + x^2

x^2 = 19^2 - 12^2

x^2 = 361 - 144

x^2 = 217

x = $\sqrt{217}$

x = 14.73

5 0

2 years ago

Alice purchased 4 1⁄2 kilograms of olive oil for $27. What is the price per kilogram

Bas_tet [7]

Do 27 divided by 4 1/2 or 4.5. That will be your answer. Let me know if this helps!

5 0

2 years ago

Read 2 more answers

What is the least common multiple of 1/2, 1/3, 4/5, 3/10

Salsk061 [2.6K]

15/30 10/30 24/30 9/30

6 0

2 years ago

Can someone help me in this plssss I really need it

kompoz [17]

Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$

$\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}$

6 0

3 years ago