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2 years ago

10

Solve the equation by factoring. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decim

al places where appropriate. If there is no solution, enter NO SOLUTION.)
2 cos() tan() + tan() = 1 + 2 cos()

1 answer:

ArbitrLikvidat [17]2 years ago

3 0

Answer:

What are the numbers in the parentheses?

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The unit rate would be:
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At. Camp, the counselors were organizing a relay. The teams can have 4 or 5 members. There are 36 campers. How many relay teams

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The answer is 9 as 36/4=9.

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Using the diagram below, identify the relationship of the pair of angles and find the value of x.

ziro4ka [17]

Answer:

The angles are supplementary to each other (their sum is 180 degrees)

x = 62°

Step-by-step explanation:

(2x+10) + 46 = 180

subtract 56 from each side

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divide both sides by 2

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3 years ago

What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

Sunny_sXe [5.5K]

Answer:

<h2> $\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }$ </h2>

First option is the correct option.

Step-by-step explanation:

$\frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 }$

Factor out X from the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9}$

Using ${a}^{2} - {b}^{2} = (a - b)(a + b)$ , factor the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x(x - 3)(x + 3) } - \frac{x + 1}{(x - 3)(x + 3)}$

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

$\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}$

Multiply the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}$

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}$

Distribute -x through the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x }{x(x - 3)(x + 3)}$

Using ${a}^{2} - {b}^{2} = (a + b)(a - b)$ , simplify the product

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x}{x( {x}^{2} - 9)}$

Collect like terms

$\frac{ {x}^{2} + 7x + 15 - 5}{x( {x}^{2} - 9)}$

Subtract the numbers

$\frac{ {x}^{2} + 7x + 10}{ x({x}^{2} - 9)}$

Distribute x through the parentheses

$\frac{ {x}^{2} + 7x + 10}{ {x}^{3} - 9x}$

Write 7x as a sum

$\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }$

Factor out X from the expression

$\frac{x(x + 5) + 2x + 10}{ {x}^{3} - 9x}$

Factor out 2 from the expression

$\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }$

Factor out x + 5 from the expression

$\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }$

Hope this helps...

Best regards!!

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3 years ago

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Anastasy [175]

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Or for every 12 students there's 1 adult

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