Answer:
A:- 50 J
B:- 500 J
Explanation:
a) Given that a 25 N force is applied to move the box. Also the floor is having friction surface.
So in order to move the box, the floor should have friction of atleast 25 N.
∴ friction = 25 N
Work done = force * displacement of box
Given, the box is moved 2 m across the floor
So, Work done = friction * 2 m
= 25 * 2
= 50 J
b) Given, the box is having weight of 250 N weight
Gravitational force is acting on the box which is equal to (mass * gravity)
∴ Force = 250 N
The box is lifted 2 m above the floor.
So, displacement = 2 m
Work done = force * displacement of box
Work done = 250 * 2
= 500 J
Answer:
<em>J=600 kg m/s
</em>
Explanation:
<u>Impulse And Momentum
</u>
Suppose a particle is moving at a certain speed and changes it to . The impulse J is equivalent to the change of linear momentum. The momentum can be computed by
The initial and final momentums are given, respectively, by:
Thus, the change of momentum is
It's equal to the Impulse J
Our data is
Answer:
The angular velocity of the wheel in terms of d, F, and I is, ω = d/t (F/I α) s⁻¹
Explanation:
Given,
The angular velocity ω
The displacement d
The magnitude of the applied force, F
The moment of inertia of the wheel I = mr²
The angular velocity can be written as
ω = v /r
where,
v - linear velocity
r - radius of the wheel
ω = d/t (1/r) (∵ v = d /t)
The force can be written as,
F = m a
= m α r (∵ a = α r)
Multiplying both sides by r
F r = m r² α
F r = I α (∵ I = mr²)
r = I α / F
Substituting in the above equation for ω
ω = d/t (F/I α) s⁻¹
Hence, the angular velocity of the wheel in terms of d, F, and I is, ω = d/t (F/I α) s⁻¹