Chemical reaction: SO₄²⁻ + Ba²⁺ → BaSO₄.
m(sample) = 1,543 g.
m(BaSO₄) = 0,2243 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,2243 g ÷ 233,4 g/mol.
n(BaSO₄) = 0,00096 mol.
n(BaSO₄) = n(SO₄²⁻).
ω(SO₄²⁻) = m(SO₄²⁻) ÷ m(sample).
ω(SO₄²⁻) = 0,00096 mol · 96 g/mol ÷ 1,543 g.
ω(SO₄²⁻) = 0,059 = 5,9%.
<h3>
Answer:</h3>
5.2 mol H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 6HCl + Fe₂O₃ → 2FeCl₃ + 3H₂O
[Given] 10.4 mol HCl
<u>Step 2: Identify Conversions</u>
[RxN] 6 mol HCl = 3 mol H₂O
<u>Step 3: Stoichiometry</u>
- Set up:

- Multiply/Divide:

Density is defined as mass per unit volume.

the mass of 1 mL of CO₂ is - 0.0019 g
3.5 L = 3500 mL
then the mass of 3500 mL of CO₂ is - 0.0019 g/mL x 3500 mL = 6.65 g
mass of 3.5 L of CO₂ is 6.65 g
D.) He arranged elements by Atomic Masses
Heat of vaporization (During which the temperature stays the same)