Answer:
It is always twice the value of the actual yield.
Explanation:
Answer:
19 °C
Explanation:
Step 1: Given and required data
- Mass of granite (m): 20 g
- Heat absorbed (Q): 300. 2 J
- Specific heat capacity of granite (c): 0.790 J/g.°C
Step 2: Calculate the temperature change (ΔT)
We will use the following expression.
Q = c × m × ΔT
ΔT = Q/c × m
ΔT = 300.2 J/(0.790 J/g.°C) × 20 g = 19 °C
Answer:
![\% Cu=45.2\%\\\\\% Zn=53.6\%\\\\\% Pb=1.2\%](https://tex.z-dn.net/?f=%5C%25%20Cu%3D45.2%5C%25%5C%5C%5C%5C%5C%25%20Zn%3D53.6%5C%25%5C%5C%5C%5C%5C%25%20Pb%3D1.2%5C%25)
Explanation:
Hello!
In this case, given the masses of copper, zinc and lead, it is possible to compute the moles via their atomic masses first:
![n_{Cu}=\frac{91.0gCu}{63.55g/mol}=1.432mol\\\\ n_{Zn}=\frac{111gZn}{65.41g/mol}=1.697mol\\\\n_{Pb}=\frac{7.51gPb}{207.2g/mol}=0.0362mol\\](https://tex.z-dn.net/?f=n_%7BCu%7D%3D%5Cfrac%7B91.0gCu%7D%7B63.55g%2Fmol%7D%3D1.432mol%5C%5C%5C%5C%20n_%7BZn%7D%3D%5Cfrac%7B111gZn%7D%7B65.41g%2Fmol%7D%3D1.697mol%5C%5C%5C%5Cn_%7BPb%7D%3D%5Cfrac%7B7.51gPb%7D%7B207.2g%2Fmol%7D%3D0.0362mol%5C%5C)
Now, we compute the atomic percentages as shown below:
![\% Cu=\frac{1.432}{1.432+1.697+0.0362}*100\% =45.2\%\\\\\% Zn=\frac{1.697}{1.432+1.697+0.0362}*100\%=53.6\%\\\\\% Pb=\frac{0.0362}{1.432+1.697+0.0362}*100\%=1.2\%](https://tex.z-dn.net/?f=%5C%25%20Cu%3D%5Cfrac%7B1.432%7D%7B1.432%2B1.697%2B0.0362%7D%2A100%5C%25%20%3D45.2%5C%25%5C%5C%5C%5C%5C%25%20Zn%3D%5Cfrac%7B1.697%7D%7B1.432%2B1.697%2B0.0362%7D%2A100%5C%25%3D53.6%5C%25%5C%5C%5C%5C%5C%25%20Pb%3D%5Cfrac%7B0.0362%7D%7B1.432%2B1.697%2B0.0362%7D%2A100%5C%25%3D1.2%5C%25)
Best regards!
I think the answer is a). There are 20 kinds of amino acid can form peptides and proteins. There are many possible combinations. And there are also different folding forms and structure that can lead differences in properties.
it has no effect on the blue litmus.
When it's tested on the red litmus paper it turns blue