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3 years ago

Which is not an example of a vestigial structure

Chemistry

2 answers:

neonofarm [45]3 years ago

6 0

Answer:

Pelvic bone of a snake

Explanation:

fenix001 [56]3 years ago

3 0

Answer:

the femur

Explanation:

a vestigial structure is useless, and a femur bone is not uselsess

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Help please thank you

Vikki [24]

Answer:

B I think I am pretty sure

8 0

3 years ago

Which of the following is diamagnetic?

zlopas [31]

Answer:

the answer is

E) All are paramagnetic

Explanation:

hope this helps u!!!

3 0

4 years ago

Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of

Brut [27]

Answer: The smallest temperature change is shown by water.

Explanation:

To calculate the heat absorbed or released, we use the equation:

$q=mC\times \Delta T$ ......(1)

where,

q = heat absorbed = 200.0 J

m = mass of the substance

C = specific heat of substance

$\Delta T$ = change in temperature

As, the same amount of heat is getting absorbed in all the cases. So, the change in temperature will depend on the product of mass and specific heat.

For the given options:

Option a: 50.0 g Fe, $C_{Fe}=0.449J/g^oC$

We are given:

$m=50.0g\\C_{Fe}=0.449J/g^oC$

Putting values in equation 1, we get:

$200.0J=50.0g\times 0.449J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{50\times 0.449}=8.99^oC$

Change in temperature = 8.99°C

Option b: 50.0 g water, $C_{water}=4.18J/g^oC$

We are given:

$m=50.0g\\C_{water}=4.18J/g^oC$

Putting values in equation 1, we get:

$200.0J=50.0g\times 4.18J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{50\times 4.18}=0.96^oC$

Change in temperature = 0.96°C

Option b: 25.0 g Pb, $C_{Pb}=0.128J/g^oC$

We are given:

$m=50.0g\\C_{Pb}=0.128J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.128J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.128}=62.5^oC$

Change in temperature = 62.5°C

Option d: 25.0 g Ag, $C_{Ag}=0.235J/g^oC$

We are given:

$m=25.0g\\C_{Ag}=0.235J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.235J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.235}=34.04^oC$

Change in temperature = 34.04°C

Option e: 25.0 g granite, $C_{granite}=0.79J/g^oC$

We are given:

$m=25.0g\\C_{Fe}=0.79J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.79J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.79}=10.13^oC$

Change in temperature = 10.13°C

Hence, the smallest temperature change is shown by water.

5 0

3 years ago

The reaction A( g ) ⇌ 2 B( g ) A(g) ⇌ 2 B(g) has an equilibrium constant of K = 0.010 K = 0.010. What is the equilibrium constan

Over [174]

Answer:

K = 10

Explanation:

Using Hess's law, it is possible to obtain the equilibrium constant, K, of a reaction using K of similar reactions. For example:

If A ⇄ B K = X

B ⇄ A K = 1/X

2A ⇄ 2B K = X².

Thus, if A(g) ⇄ 2B(g) K = 0.010

2B(g) ⇄ A(g) K = 1 / 0.010; K = 100

B(g) ⇄ A(g) K = √100 = 10

5 0

3 years ago

How many different chlorinated products

valentina_108 [34]

Answer: if I’m not mistaken it would be 8

Explanation:

3 0

3 years ago