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3 years ago

Is cooking raw tomatoes a physical or a chemical change?Explain why?

1 answer:

7 0

When you are asked a question like this, you can always ask yourself this question. Can I change it back after this change? For example, if you are burning wood, you cannot bring it back to wood after you burn it, therefore, it is a chemical change. However, if you boil and evaporate water, you can make the water condense again back into its liquid form. In this case, you cannot bring the tomato back to its raw state. Therefore, cooking raw tomatoes is a chemical change.

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Explain how mary would conduct a science experiment to test wheather plants need soil to grow.

Elis [28]

Try to grow a plant with and without soil

6 0

2 years ago

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Which is the correct order for a food chain?

Zigmanuir [339]

C because first comes the source or producer than the first eater then the second and then it decomposes

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3 years ago

Consider the reaction 2NO(g) 1 O2(g) ¡ 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is reac

GalinKa [24]

<h2>a) The rate at which $NO_2$ is formed is 0.066 M/s</h2><h2>b) The rate at which molecular oxygen $O_2$ is reacting is 0.033 M/s</h2>

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of $NO$ = $-\frac{1d[NO]}{2dt}$ = 0.066 M/s

Rate in terms of disappearance of $O_2$ = $-\frac{1d[O_2]}{dt}$

Rate in terms of appearance of $NO_2$ = $\frac{1d[NO_2]}{2dt}$

1. The rate of formation of $NO_2$

$-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}$

$\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s$

2. The rate of disappearance of $O_2$

$-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}$

$-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s$

Learn more about rate law

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https://brainly.in/question/1297322

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3 years ago

In which layer(s) would a solid cube with 6 cm sides and mass of 270 g float? Explain.

DIA [1.3K]

The buoyancy of an object is dictated by its density. So let us calculate for density, where:density = mass / volume
Calculate the volume first of a solid cube:volume = (6 cm)^3 = 216 cm^3 = 216 mL
Therefore density is:density = 270 g / 216 mLdensity = 1.25 g / mL
Therefore this object will float in the layer in which the density is more than 1.25 g / mL.

6 0

3 years ago

The length of the school's gymnasium is 30 meters long. How many centimeters long is the school's gymnasium

aleksley [76]

Answer:

The answer to your question is: 3000 cm

Explanation:

30 meters long to cm

We can use a rule of three to solve it

We know that 1 meter ------------------ 100 cm

30 meters ---------------- x

x = 30(100)/1 = 3000 cm

5 0

3 years ago

Read 2 more answers