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Mumz [18]
1 year ago
10

What evidence supports the conclusion that a chemical reaction has occurred?

Physics
1 answer:
GalinKa [24]1 year ago
3 0

Answer:

Precipitation formed

Temperature change

fizzing and hissing

bubbles

change in state

Explanation:

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Please correct answers only, if you don’t know, ignore. Please answer this or am I correct?
Wewaii [24]

Answer:

C is correct.

Explanation:

5 0
3 years ago
Read 2 more answers
A high jumper jumps over a bar that is 2 m above the mat. With what velocity does the jumper strike the mat in the landing area?
docker41 [41]

Answer:

The velocity with which the jumper strike the mat in the landing area is 6.26 m/s.

Explanation:

It is given that,

A high jumper jumps over a bar that is 2 m above the mat, h = 2 m

We need to find the velocity with which the jumper strike the mat in the landing area. It is a case of conservation of energy. let v is the velocity. it is given by :

v=\sqrt{2gh}

g is acceleration due to gravity

v=\sqrt{2\times 9.81\ m/s^2\times 2\ m}

v = 6.26 m/s

So, the velocity with which the jumper strike the mat in the landing area is 6.26 m/s. Hence, this is the required solution.

8 0
3 years ago
Prior to the Panama Canal, __________ was a major route between the Atlantic and Pacific oceans.
Bingel [31]
The Rio Grande was the major route prior to the Panama Canal.
3 0
3 years ago
Read 2 more answers
All of the following devices are used to create an open circuit EXCEPT a:
Brrunno [24]

Answer:

I think its a fuse because everything else makes sense and is used in electrical circuits and the fuse is the only one that stands out to me  ¯\_(ツ)_/¯

4 0
2 years ago
To what temperature will a 79.0 g piece of glass raise if it absorbs 9457 calories of heat and its specific heat capacity is 0.5
ruslelena [56]

Answer:

T_final = 279.4 [°C]

Explanation:

In order to solve this problem, we must use the following equation of thermal energy.

Q=m*C_{p}*(T_{f}-T_{i})

where:

Q = heat = 9457 [cal]

m = mass = 79 [g] = 0.079 [kg]

Cp = specific heat = 0.5 [cal/g*°C]

T_initial = initial temperature = 40 [°C]

T_final = final temperature [°C]

9457 = 79*0.5*(T_{f}-40)\\239.41=T_{f}-40\\\\T_{f}=279.4[C]

8 0
2 years ago
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